Y=x-1 eqn 1
y=-3x-5 eqn 2
subtracting 1 from 2 we get
0 = 4x + 4
hence x= -1
therefore y = -1-1 = -2
so (-1,-2 ) falls in III quad.
Answer:
y = 1x + 2
Step-by-step explanation:
To fill in slope intercept form(y = mx + b) identify the initial value(b) and slope(m).
The initial value is the y coordinate when the x coordinate is 0. It is also known as the point where the line crosses the y axis. This point on the graph is (0, 2). So, the initial value is 2.
Slope is identified by finding a point on the graph that the line passes through and creating a right triangle to a point that is even with both point. Then, divide the y coordinate of that point by its x coordinate. One coordinate you could use is point (-2, 2). 2 divided by -2 is -1. But, since the line has a positive association, the slope is going to be a positive number. So, the slope is 1.
Now fill in the the slope intercept form.
y = mx + b ---> y = 1x + 2
Answer:
Hi how are you what are you looking for
Answer:
Chaos
Lack of understanding for how to behave
Disregard for other people
Step-by-step explanation: