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s2008m [1.1K]
3 years ago
10

What is an arithmetic progressions??​

Mathematics
2 answers:
prisoha [69]3 years ago
8 0

Answer:

Hi how are you what are you looking for

Anton [14]3 years ago
8 0

<em>a sequence of numbers in which each differs from the preceding one by a constant quantity (e.g. 1, 2, 3, 4, etc.; 9, 7, 5, 3, etc.).</em>

<em>a sequence of numbers in which each differs from the preceding one by a constant quantity (e.g. 1, 2, 3, 4, etc.; 9, 7, 5, 3, etc.).the relation between numbers in an arithmetic progression.</em>

<em>\huge \mathfrak \pink{hope \: it \: helps}</em>

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24 right handed students

Step-by-step explanation:

1. Out of every 5 students, 4 are right handed and 1 is left handed. We can say that 1/5 of the class is left handed.

2. Multiply 30 by 1/5 to get 6 left handed students in the class.

3. Take the 30 students in the class and subtract the 6 left handed students.

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The combined weight of 2 identical dice, 5 identical balls and 4 identical marbles was 260 grams. The combined weight of one die
olya-2409 [2.1K]

Answer:

The total weight of one die, one ball, and one marble is 75 grams.

Step-by-step explanation:

Consider the provided information.

Let d represents the number of dice, b represents the number of balls and m represents the number of marbles.

So according to the question.

The combined weight of 2 identical dice, 5 identical balls and 4 identical marbles was 260 grams.

2d+5b+4m=260  ....(1)

The combined weight of one die and one marble was 55 grams.

d+m=55

m=55-d  ....(2)

3 balls weighed the same as two dice.

3b=2d

Multiply both sides by 5 and divide by 3.

5b=\frac{10}{3}d  .....(3)

Now put the value of equation 2 and 3 in equation 1.

2d+\frac{10}{3}d+4(55-d)=260

2d+\frac{10}{3}d+220-4d=260

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d=30

Put d=30 in equation 2.

m=55-30

m=25

Put d=30 in equation 3.

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5b=100

b=20

The total weight (in grams) of one die, one ball, and one marble is:

d+m+b=25+20+30

d+m+b=75

The total weight of one die, one ball, and one marble is 75 grams.

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