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2 years ago

Evaluate the expression is 4*3^z when c is 2

Mathematics

1 answer:

AfilCa [17]2 years ago

4 0

Hey there!

ASSUMING….

4 * 3^c

= 4 * 3^2

= 4 * 3 * 3

= 12 * 3

≈ 12 + 12 + 12

≈ 24 + 12

= 36

Therefore, the answer should be: 36

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

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John types 62 words per minute. Which an expression for the number of words he types in m minutes?

andrezito [222]

Answer:

w = 62m

Step-by-step explanation:

We need to make an expression for the numbers of words (w) John types in m minutes.

We know he types 62 words in 1 minute, so 62 is the coefficient of m.

The dependent variable here is w, so that should on the left of the equal sign.

m, on the other hand, is independent, so that's on the right of the equal sign.

So, the expression is w = 62m.

8 0

3 years ago

Consider the population of all 1-gallon cans of dusty rose paint manufactured by a particular paint company. Suppose that a norm

Artemon [7]

Answer:

a) 0.5.

b) 0.8413

c) 0.8413

d) 0.6826

e) 0.9332

f) 1

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 6, \sigma = 0.2$

(a) P(x > 6) =

This is 1 subtracted by the pvalue of Z when X = 6. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6-6}{0.2}$

$Z = 0$

$Z = 0$ has a pvalue of 0.5.

1 - 0.5 = 0.5.

(b) P(x < 6.2)=

This is the pvalue of Z when X = 6.2. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6.2-6}{0.2}$

$Z = 1$

$Z = 1$ has a pvalue of 0.8413

(c) P(x ≤ 6.2) =

In the normal distribution, the probability of an exact value, for example, P(X = 6.2), is always zero, which means that P(x ≤ 6.2) = P(x < 6.2) = 0.8413.

(d) P(5.8 < x < 6.2) =

This is the pvalue of Z when X = 6.2 subtracted by the pvalue of Z when X 5.8.

X = 6.2

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6.2-6}{0.2}$

$Z = 1$

$Z = 1$ has a pvalue of 0.8413

X = 5.8

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5.8-6}{0.2}$