Question

A. Find the value of x that maximizes the area of the figure.

Answer 1

Step-by-step explanation:

the area is

$A=\frac{(12+12-4x)(x+2)}{2}\\=2(6-x)(x+2)\\=-2x^2+8x+24\\=-2(x^2-4x+4)+32\\=-2(x-2)^2+32$

will max if

a. x = 2

and the max area is

b 32