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2 years ago

10

On a map one inch is equal to 125 miles. There are six inches between Happyville and Glumtown. How many miles are between the tw

o towns?
(I will make brainliest)

1 answer:

erma4kov [3.2K]2 years ago

8 0

<h2>Answer:</h2><h2> 750</h2>

Step-by-step explanation:

6x125=750 hope this helps

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Which equation has the solutions x=1+or-square root of 5?

stiv31 [10]

We will proceed to solve each case to determine the solution of the problem.

<u>case a)</u> $x^{2}+2x+4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}+2x=-4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}+2x+1=-4+1$

$x^{2}+2x+1=-3$

Rewrite as perfect squares

$(x+1)^{2}=-3$

$(x+1)=(+/-)\sqrt{-3}\\(x+1)=(+/-)\sqrt{3}i\\x=-1(+/-)\sqrt{3}i$

therefore

case a) is not the solution of the problem

<u>case b)</u> $x^{2}-2x+4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}-2x=-4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}-2x+1=-4+1$

$x^{2}-2x+1=-3$

Rewrite as perfect squares

$(x-1)^{2}=-3$

$(x-1)=(+/-)\sqrt{-3}\\(x-1)=(+/-)\sqrt{3}i\\x=1(+/-)\sqrt{3}i$

therefore

case b) is not the solution of the problem

<u>case c)</u> $x^{2}+2x-4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}+2x=4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}+2x+1=4+1$

$x^{2}+2x+1=5$

Rewrite as perfect squares

$(x+1)^{2}=5$

$(x+1)=(+/-)\sqrt{5}\\x=-1(+/-)\sqrt{5}$

therefore

case c) is not the solution of the problem

<u>case d)</u> $x^{2}-2x-4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}-2x=4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}-2x+1=4+1$

$x^{2}-2x+1=5$

Rewrite as perfect squares

$(x-1)^{2}=5$

$(x-1)=(+/-)\sqrt{5}\\x=1(+/-)\sqrt{5}$

therefore

case d) is the solution of the problem

therefore

<u>the answer is</u>

$x^{2}-2x-4=0$

5 0

3 years ago

Read 2 more answers

Can anyone help me figure this out / explain it to me pls .. ="(

Bad White [126]

Um I think your teacher might be high

8 0

3 years ago

Use the figure and information below to find the length of each line segment

Hitman42 [59]

Answer:

7. 6

8. 6

9. 12

10. 6

11. 12

12. 24

Step-by-step explanation:

3 0

3 years ago

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Which is not a true statement? A - 8 < 7 C 7 > - 8 B - 8 > - 7 D 7 < 8

spayn [35]

Answer:

B: -8>-7

Step-by-step explanation:

-8 is 1 less than -7

8 0

3 years ago

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What’s the square root of -121

irakobra [83]

The answer is 11 i

<em /><em>Explanation:
</em>
The square root needs to be a number that can be multiplied by itself and equal the original number.

In this case, the number is 11, 11*11 = 121

However, you are looking for the square root of a negative number, due to this you would add i to the answer,
i = imaginary number, or -

( Depending on your grade/ teacher however, you can put "no solution"

5 0

3 years ago