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skad [1K]
2 years ago
15

Help ASAPPPPP PLEASE!

Mathematics
2 answers:
kkurt [141]2 years ago
6 0
1.5 3/8
2.37/12
3.7 11/15
4.15/8
5. 68/12
6.2 7/15
7.57/12
8.613
Thope this
helps! I
am a teacher
Who teaches
This
Material
So it is a
pleasure to
help Students
Solve these problems!
lilavasa [31]2 years ago
4 0

Answer:

1. 5 3/8

2. 3 7/12

3.7 11/15

4. 1 5/8

5. 6 8/12

6.2 7/15

7. 5 7/12

8. 6 1/3

Step-by-step explanation:

Hope this helps have a great day Sry if I got any wrong

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I don't understand. Please help answer questions!!!!!!
insens350 [35]
16) yes, they are reflections on a summit.
17) no parallelogram shown to answer question <span />
7 0
3 years ago
I really am confused on how to write a proof.
kvasek [131]

Since ABCD is a parallelogram, the opposite sides will be parallel and equal,

\begin{gathered} AB=CD \\ BC=AD \end{gathered}

Consider that AC acts as a transversal to the parallel lines AB and CD, so we can write,

\begin{gathered} \angle CAD=\angle ACB\text{ (Alternate Interior Angles)} \\ BC=AD\text{ (Opposite sides of parallelogram)} \\ \angle ADB=\angle CBD\text{ (Alternate Interior Angles)} \end{gathered}

So by the ASA criteria, the triangle AED is congruent to the triangle CEB,

Then the corresponding parts of the triangles will be equal,

\begin{gathered} AE=CE \\ BE=DE \end{gathered}

Hence Proved.

8 0
1 year ago
A right triangle has coordinates A(6, 0), B(0, 0), and C(0, 8). What is the perimeter of the triangle?
dimulka [17.4K]

Answer:

C

Step-by-step explanation:

From the given coordinates

A(6, 0), B(0, 0) then AB = 6 - 0 = 6

B(0, 0), C(0, 8) then BC = 8 - 0 = 8

To calculate AC use Pythagoras' theorem on the right triangle formed

AC² = AB² + BC² = 6² + 8² = 36 + 64 = 100

Take the square root of both sides, hence

AC = \sqrt{100} = 10

Perimeter = AB + BC + AC = 6 + 8 + 10 = 24 → C

5 0
3 years ago
How to tell if an ordered pair is a solution to a function
Evgen [1.6K]
A) yes
B) yes
C) no

For each of these, substitute the value of x in the ordered pair into x in the function.

For A, x = -5; -5<2, so the piece of the function we want is f(x) = 3.  In our ordered pair, y=f(x)=3, so yes, it is a solution.

For B, x = 2; 2≤2<6, so the piece of the function we want is f(x) = -x+1.  In our ordered pair, y=f(x)=-1; -2+1=-1, so yes, it is a solution.

For C, x = 8; 8≥6, so the piece of the function we want is f(x) = x.  In our ordered pair, y=f(x)=-7; -7≠8, so no, it is not a solution.
5 0
3 years ago
Showing ALL calculations, whether this statement is valid
choli [55]

Answer:

<em>R</em><em>M</em>79 608.51

Step-by-step explanation:

First year,

<em>RM</em>505 050.00×5%=<em>RM</em>505 050.00×5/100

=<em>RM</em>25 252.50

second year,

(<em>RM</em>505 050.00+<em>R</em><em>M</em>25 252.50)×5%=<em>RM</em>530 302.50×5/100

=<em>RM</em>26 515.13

third year,

(<em>R</em><em>M</em>530 302.50+<em>R</em><em>M</em>26 515.13)×5%=<em>R</em><em>M</em>556817.63×5/100

=<em>R</em><em>M</em>27840.88

three years interest,

<em>RM</em>25 252.50+<em>RM</em>26 515.13+<em>RM</em>27840.88=<em>RM</em>79608.51

<em><u>I</u></em><em><u> </u></em><em><u>d</u></em><em><u>o</u></em><em><u>n</u></em><em><u>'</u></em><em><u>t</u></em><em><u> </u></em><em><u>k</u></em><em><u>n</u></em><em><u>o</u></em><em><u>w</u></em><em><u> </u></em><em><u>t</u></em><em><u>h</u></em><em><u>a</u></em><em><u>t</u></em><em><u> </u></em><em><u>i</u></em><em><u>s</u></em><em><u> </u></em><em><u>R</u></em><em><u> </u></em><em><u>o</u></em><em><u>r</u></em><em><u> </u></em><em><u>R</u></em><em><u>M</u></em><em><u> </u></em>

<em><u>i</u></em><em><u>f</u></em><em><u> </u></em><em><u>i</u></em><em><u>t</u></em><em><u> </u></em><em><u>i</u></em><em><u>s</u></em><em><u> </u></em><em><u>R</u></em><em><u> </u></em><em><u>,</u></em><em><u>s</u></em><em><u>o</u></em><em><u>r</u></em><em><u>r</u></em><em><u>y</u></em>

<u>H</u><u>o</u><u>p</u><u>e</u><u> </u><u>c</u><u>a</u><u>n</u><u> </u><u>h</u><u>e</u><u>l</u><u>p</u><u>!</u>

8 0
3 years ago
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