Answer:
this is the anwser
Step-by-step explanation:
4 12 13 triangle
Obtuse scalene triangle.
Sides: a = 4 b = 12 c = 13
Area: T = 23.894
Perimeter: p = 29
Semiperimeter: s = 14.5
Angle ∠ A = α = 17.839° = 17°50'19″ = 0.311 rad
Angle ∠ B = β = 66.782° = 66°46'55″ = 1.166 rad
Angle ∠ C = γ = 95.379° = 95°22'46″ = 1.665 rad
Height: ha = 11.947
Height: hb = 3.982
Height: hc = 3.676
Median: ma = 12.349
Median: mb = 7.517
Median: mc = 6.144
Inradius: r = 1.648
Circumradius: R = 6.529
Vertex coordinates: A[13; 0] B[0; 0] C[1.577; 3.676]
Centroid: CG[4.859; 1.225]
Coordinates of the circumscribed circle: U[6.5; -0.612]
Coordinates of the inscribed circle: I[2.5; 1.648]
Exterior (or external, outer) angles of the triangle:
∠ A' = α' = 162.161° = 162°9'41″ = 0.311 rad
∠ B' = β' = 113.218° = 113°13'5″ = 1.166 rad
Answer:
(4,3)
Step-by-step explanation:
Given
x^2+y^2=25
x-y^2=-5
In order to solve the equations, from equation 2 we get
-y^2= -5-x
y^2=5+x
Putting the value of y^2 in equation 1
x^2+5+x=25
x^2+5-25+x=0
x^2+x-20=0
x^2+5x-4x-20= 0
x(x+5)-4(x+5)=0
(x+5)(x-4)=0
So
x+5=0 x-4=0
x=-5 x=4
Now for x=-5
x^2+y^2=25
(-5)^2+y^2=25
25+y^2=25
y^2=25-25
y^2=0
so Y=0
And for x = 4
x^2+y^2=25
(4)^2+y^2=25
16+y^2=25
y^2=25-16
y^2=9
y= ±3
So the solution to the system of equations is
(-5,0) , (4,3), (4,-3)
The only solution that belongs to first quadrant is (4,3)
Um...thats a tough one... well first you have to put the formula together which is pi(10)(26)+pi(10)^2 multiply 10 times 26 then 10 times ten giving us a much more easier equation 260pi + 100pi. we can cross off answer A and answer C just by looking at the simplified equation. now add the two together, giving us 360pi inches^2
The answer is 1761 1/2 (1761.5 in decimal form)
12 because the 23 3/8 is rounded down and the 11 2/9 is rounded down as well
