What do I need to subtract from to get angle two?
1 answer:
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Answer:
y-intercept: 10
concavity: function opens up
min/max: min
Step-by-step explanation:
1.) The definition of a y-intercept is what the resulting value of a function is when x is equal to 0.
Therefore, if the function's equation is given, to find y-intercept simply plug in 0 for the x-values:
y intercept ( f(0) )= 10
2.) In order to find concavity (whether a function opens up or down) of a quadratic function, you can simply find the sign associated with the x^2 value. Since 2x^2 is positive, the concavity is positive. This is basically possible, since it is identifying any reflections affecting the y-values / horizontal reflections.
3.) In order to find whether a quadratic function has a maximum or minimum, you can use the concavity of the function. The idea is that if the function opens downwards, the vertex would be at the very top, resulting in a maximum. If a function was open upwards, the vertex would be at the very bottom, meaning there is a minimum. Like the concavity, if the value associated with x^2 is positive, there is a minimum. If it is negative, there is a maximum. Since 2x^2 is positive, the function has a minimum.
Similar shapes may or may not be congruent.
The value of x is (a) 9.0
The corresponding sides are:
- AB and DE
- BC and EF
- AC and DF
The side lengths are:
Because the shapes are congruent, and AC corresponds to DF.
This means that:
So, we have:
Collect like terms
Divide both sides by 5
<em>Hence, the correct option is (a) 9.0</em>
Read more about congruent triangles at: