Question

Write a quadratic equation that has only one real-number solution

Answer 1

The equation that has only one real number solution is

4a²x²+4abx+ b² = 0 and the solution is x = -b/2a where a, b, and c are real values.

What is a quadratic equation?

Any equation of the form $\rm ax^2+bx+c=0$ Where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.

As we know, the formula for the roots of the quadratic equation is given by:

$\rm x = \dfrac{-b \pm\sqrt{b^2-4ac}}{2a}$

If the quadratic equation has only one solution, then

$\rm b^2 - 4ac = 0$   or

$\rm b^2 = 4ac$

$\rm x = \dfrac{-b}{2a}$

2ax = - b

(2ax+b) = 0

(2ax+b)² = 0  (square on both sides)

$\rm 4a^2x^2 + 4abx+ b^2 = 0$

Thus, the equation that has only one real number solution is

4a²x²+4abx+ b² = 0 and the solution is x = -b/2a where a, b, and c are real values.

Learn more about quadratic equations here:

brainly.com/question/2263981

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