Answer:
A non-equilateral rhombus.
Step-by-step explanation:
We can solve this graphically.
We start with square:
ABCD
with:
A = (11, - 7)
B = (9, - 4)
C = (11, - 1)
D = (13, - 4)
Only with the vertices, we can see that ABCD is equilateral, as the length of each side is:
AB = √( (11 - 9)^2 + (-7 -(-4))^2) = √( (2)^2 + (3)^2) = √(4 + 9) = √13
BC = √( (11 - 9)^2 + (-1 -(-4))^2) = √13
CD = √( (11 - 13)^2 + (-1 -(-4))^2) = √13
DA = √( (11 - 13)^2 + (-7 -(-4))^2) = √13
And we change C by C' = (11, 1)
In the image you can see the 5 points and the figure that they make:
The figure ABCD is a rhombus, and ABC'D is also a rhombus, the only difference between the figures is that ABCD is equilateral while ABC'D is not equilateral.
Answer:
kurt
Step-by-step explanation:
It’s a bit blurry retake the picture
X = 2
y = 1
You can get this by replacing the y in the second equation with the 3x - 5 from the first. Then solve for x. Once you have that value, you can solve for y.
Put in order from smallest to largest
–9, –4, –1, 2, 3, 5, 7
Minimum = –9<span>
Maximum = 7
</span>Range = 7 - (-9) = 7 + 9 = 16
Range = the difference between the maximum and minimum data values
hope it helps