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zaharov [31]
3 years ago
6

greg invested $20 and qudrupled his money in five years.sabrena also invested $20 and after five years the amount was eqaul to 2

0 to the fourth power who had more money after five years.
Mathematics
1 answer:
const2013 [10]3 years ago
6 0

Answer:

The money of Greg after five years is $80

The money of Sabrena after five years is $160,000

So,The money of Sabrena is more than Greg after five years .

Step-by-step explanation:

Given as :

Greg invested $20 and quadrupled his money in five years

Let the quadrupled money after five years = $x

∵ quadrupled means the money becomes 4 times of previous

So, x = $20 × 4

i.e x = $80

So, The money of Greg after five years is $80

Again

Sabrena invested $20 and after five years money becomes 20 to the fourth power

Let the money after 20 to the fourth power = $y

So, y = 20^{4}

i.e y = 160,000

So, The money of Sabrena after five years is $160,000

∵ Sabrena money is more than Greg money

Hence, The money of Sabrena is more after five years . Answer

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Answer:

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Step-by-step explanation:

Volume of cube: s³

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_____________________

32ft^3 and 1372ft^3 →

32 : 1372 = 8 : 343

343 / 8 = 42 ⅞ = 42.875

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2 years ago
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A survey of 90 men found that an average amount spent on St. Patrick's day of $55 with a standard deviation of $18. A similar su
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Answer:

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Step-by-step explanation:

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<em>H</em>ₐ: Men spend more than women on St. Patrick's day, i.e. μ₁ > μ₂.

The population standard deviations are not known.

So a <em>t</em>-distribution will be used to perform the test.

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Compute the value of the test statistic as follows:

t=\frac{\bar x_{1}-\bar x_{2}}{\sqrt{\frac{s^{2}_{1}}{n_{1}}+\frac{s^{2}_{2}}{n_{2}}} }=\frac{55-44}{\sqrt{\frac{15^{2}}{90}+\frac{16^{2}}{86} }}=4.70

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3 years ago
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Answer:

a) Z = -0.8

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Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

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