The value of x when the line segment st is dilated to create line s't' about point q is 2.5 units
<h3>How to determine the value of x?</h3>
The given parameters are:
qs = 2
qt = 1.2
tt' = 1.5
ss' = x
To calculate the value of x, we make use of the following equivalent ratio
ss' : qs = tt' : qt
So, we have:
x : 2 = 1.5 : 1.2
Express as fractions
x/2 = 1.5/1.2
Multiply both sides by 2
x = 2 * 1.5/1.2
Evaluate the product
x = 2.5
Hence, the value of x is 2.5 units
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Answer:
403+40√3 ft^2
Step-by-step explanation:
(20+√3)(20+√3)
400+20√3+20√3+3
403+40√3
Hopes this helps please mark brainliest
Answer:15 boxes with 4 left over have a great day :)
Step-by-step explanation:
Answer:
2
Step-by-step explanation:
its hard to type
Answer:
solutions at -1 and 11
Step-by-step explanation:
(-b ± √b²-4ac) / 2a
in this problem, a = 1, b = -10, c = -11
(10±√100-4(-1)(-11)) / 2(1) =
(10 + √144) / 2 = 22/2 = 11
(10 - √144) / 2 = -2 / 2 = -1
