Mr. Sato needs 9 magnets.
Explanation:
AS there are 24 students in the science class,
there are <span><span>242</span>=12</span> pair of students.
Mr. Sato wants to give each pair of students 3 magnets
Mr. Sato has already given 9 pairs of students their 3 magnets
Therefore number of pairs of students yet to be given magnets is <span>12−9=3</span>.
For them he needs <span>3×3=9</span> magnets.
The chosen topic is not meant for use with this type of problem. Try the examples below.
Answer:
I believe it is 2(x-5)²−1
Step-by-step explanation:
The parentheses represent the horizontal shift. (X-__) is a shift to the right. (X+__) is a shift to the left. The last number of the function is the vertical shift. A negative number is shifting down and a post number is shifting up.
So, if the graph shifts up three units, then you add 3 + -4 to get -1. And if the graph shifts right 2 units, then you subtract 2 from -3 to get -5.
Answer:
Step-by-step explanation:
1) we have to find the area of the cut out portion
Since both circles in one side makes up the side 28cm
The diameter of each circle is 14cm
radius = diameter / 2
r = 7cm
Area of a circle = πr²
A = 22/7 × 7²
= 22/7 × 7 × 7
= 22 × 7 = 154cm²
So the four circles will make
= 154 + 154 + 154 + 154
= 616 cm²
The Area of the square will be
= L × L
= 28 × 28
= 784 cm²
Therefore the area of the remaining portion will be
Area of the square - total area of the circles
= 784 cm² - 616 cm²
= 168 cm²
The area of the remaining part is 168 cm²
