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gogolik [260]
2 years ago
5

This cuboid is made from 6 small cubes. Write how many small cubes there are in this cuboid

Mathematics
1 answer:
Alexxx [7]2 years ago
3 0

Answer:

30 cubes

Step-by-step explanation:

To find the number of small cubes in the larger cuboid, you can multiply the number of cubes that make up the length, width and height together.

There are 5 cubes along the bottom,  2 along the side and 3 going up. The volume would be 5 × 2 × 3 which is 30 cubes.

Hope this helps!

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A company is allowed to interview candidates until two qualified candidates are found. But budget constraints dictate that no mo
Lapatulllka [165]

Answer:

Kindly check attached picture for sample space design

45 ways

Step-by-step explanation:

Number of qualified candidates to be chosen = 2

Number of candidates to be interviewed = 10

Combination formula :

nCr = n! / (n-r)! r!

10C2 = 10! ÷ (10 - 2)!2!

10C2 = 10*9 / 2 * 1

10C2 = 90/2

10C2 = 45 different samples

Our sample space will contain 45 different samples

4 0
3 years ago
Subtract. (6x - 3) - (2x -2) What is the answer?
kirill115 [55]
4x-1 all u got to do is remove the parentheses and collect the like terms
6 0
3 years ago
10 cm<br>12 cm find area each shaded area​
Wewaii [24]
Do u have a diagram to show
7 0
3 years ago
How much does 1 can of soda cost if you get a
Strike441 [17]

Answer:

Each can of soda costs about 33 cents.

Step-by-step explanation:

This is just a simple division problem, and you can find the answer by dividing the cost of the sodas by the total number of sodas, so 4/12. If you complete that problem, the answer is 0.33 repeating, and since it asks you to round to the nearest hundredth, the answer is just 0.33. It is in dollar amounts, so the answer is 33 cents.

3 0
2 years ago
In the solution to this system, what is the value of y? x+y+z=1x+y+z=1 2x+y−z=82x+y-z=8 x−y+z=−5
kirza4 [7]
If you have multiple equations with multiple variables, you can either do clever substitutions, or turn it into a matrix on which you can perform linear combinations or multiplications (Gauss elimination)

1  1   1  1
2  1  -1  8
1 -1   1  -5

(note how the above 3 rows represent the 3 equations, just got rid of the variables, plus sign and equals sign)

subtract row1 from row3, that eliminates x and z from row 3.

1  1   1  1
2  1  -1  8
0 -2   0  -6

divide row3 by -2, that will give y a factor of 1

1  1   1  1
2  1  -1  8
0 1   0  3

The last row now says y=3



3 0
3 years ago
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