Answer:
See explanation
Step-by-step explanation:
Consider two triangles ABF and EDF. These triangles are two right triangles, because angles B and D are right anges.
In these triangles,
- ∠ABF ≅ ∠EDF - as two right angles;
- BF ≅ FE - given;
- ∠AFB ≅ ∠EFD - as vertical angles when two lines AD and BE itersect.
By ASA postulate (or HA postulate) these triangles are congruent, so
ΔABF ≅ ΔEDF
Congruent triangles have congruent corresponding parts, so
FA ≅ EF
A, B and C are collinear and B is in the middle.
so we have AB + BC =AC
6x +x-5= 23
7x -5=23
adding 5 to both sides
7x=23+5
7x =28
dividing both sides by 7
we get x=28/7 =4
So answer is x=4
Answer:
It is A.
Step-by-step explanation:
also, this is one question. A, B, C and D are just answers.
Answer:
a, c, b, a
Step-by-step explanation:
