3 years ago

Rocky lends $3000 to Ken at 10% per annum and the Ken lends the same sum to like at 12% per annum. Find kens gain over a period

1 answer:

6 0

Let t = time

Between Rocky and Ken:

3000 + 3000(.10)(t)

Between Ken and Mike:

3000 + 3000(.12)(t)

Kens gain = The difference

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<img src="https://tex.z-dn.net/?f=%288%20%2B%207i%29%20%2B%20%287%20-%2031%29%20" id="TexFormula1" title="(8 + 7i) + (7 - 31) "

Angelina_Jolie [31]

assuming you meant to simplify above,

$\bf (8+7i)+(7-3i)\implies \stackrel{\textit{adding like terms}}{15+4i}$

6 0

3 years ago

Read 2 more answers

Graph the equation

Lisa [10]

To find the root, replace y with 0
X^2-12x+35=0
A=1 B=-12 C=35
B^2-4ac=(-12)^2 -4(1)(35)
=144 -140
=4

x=(-b+/- square root of b^2 -4ac) /over/ (2a)
Plug in the numbers
x=-(-12) sqr (-12)^2 4(1)(35) / (2)(1)
X=12 +/-sqr 4 / 2
Positive outcome
x=12 + sqr 4 / 2
x=12+2/2
x=7 <— this one
Negative outcome
x=12-2i/2
x=6-i
Vertex: (6,-1)

8 0

3 years ago

Mia has 12 boxes of cookies. Each box contains 36 cookies. she has another 258 cookies in the pantry. How many cookies does she

lana66690 [7]

690

12×36 + 258 = 690 For extending to 20 characters

8 0

3 years ago

Point m is the midpoint of ab¯¯¯¯¯ . am=3x+3, and ab=8x−6. what is the length of am¯¯¯¯¯¯ ?

LuckyWell [14K]

As given m is a midpoint of ab. So am is half of ab.

So we can write

$am = \frac{ab}{2}$

As given am = 3x+3 , ab = 8x - 6.

So $3x+3 = \frac{8x - 6}{2}$

$3x+3 = \frac{2(4x - 3)}{2}$

$3x+3 = 4x - 3$

$3+3 = 4x - 3x
$

$6 = x$

So x = 6.

So length of am = 3x+3 = 3*6 + 3 = 21

5 0

3 years ago

What is 4/5 times 7/12

slamgirl [31]

Answer:

$\frac{28}{60}$ ( $\frac{7}{15}$ )

Step-by-step explanation:

b/c 4/5*7/12

means 4*7 and 5*12

then28/60

hope it's helpful

THANK YOU.

3 0

3 years ago