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ollegr [7]
2 years ago
10

This is for AP CALCULUS. I really need help on this. I’m trying to find the first and second derivative of these three functions

.

Mathematics
1 answer:
ale4655 [162]2 years ago
8 0

Review Material:

\sqrt[n]{x^m} = x^{\frac{m}{n}}

\frac{d}{dx}[x^n]=nx^{n-1}\\

\frac{d}{dx}[\sin(x)]=\cos(x)\\

 \frac{d}{dx}[\cos(x)]=-\sin(x)\\

\frac{d}{dx}[constant]=0\\

Step-by-step explanation:

(a)

F(x) = -2\cos(x) +x^{\frac{4}{3}} -3e\\ \text{Note: 3e is a constant}\\F'(x) = 2\sin(x) + \frac{4}{3}x^{\frac{1}{3}}\\F''(x) = 2\cos(x) + \frac{4}{9}x^{-\frac{2}{3}}

(b)

F(x) = x^{-3} + \frac{1}{2}x^2-\sin(x)\\F'(x)=-3x^{-4} + x - \cos(x)\\F''(x) = 12x^{-5} + 1 + \sin(x)

(c)

F(x) = 2x^{-3}+x^{\frac{3}{4}}-4x\\F'(x) = -6x^{-4} + \frac{3}{4}x^{-\frac{1}{4}}-4\\F''(x)= 24x^{-5} - \frac{3}{16}x^{-\frac{5}{4}}

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kykrilka [37]

Answer:

opposite\approx 70.02

Step-by-step explanation:

The triangle in the given problem is a right triangle, as the tower forms a right angle with the ground. This means that one can use the right angle trigonometric ratios to solve this problem. The right angle trigonometric ratios are as follows;

sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}\\\\tan(\theta)=\frac{opposite}{adjacent}

Please note that the names (opposite) and (adjacent) are subjective and change depending on the angle one uses in the ratio. However the name (hypotenuse) refers to the side opposite the right angle, and thus it doesn't change depending on the reference angle.

In this problem, one is given an angle with the measure of (35) degrees, and the length of the side adjacent to this angle. One is asked to find the length of the side opposite the (35) degree angle. To achieve this, one can use the tangent (tan) ratio.

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4 0
2 years ago
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