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adelina 88 [10]
2 years ago
8

Annswer this RIGHT and you'll get Brainliest

Mathematics
1 answer:
Georgia [21]2 years ago
7 0
The answer to this equation is n>-4
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One-step addi<br> Solve the equation.<br> 2 + y = 11<br> Y
harina [27]

Answer:

y= 11-2

y= 9

Step-by-step explanation:

hope you like my answer

6 0
3 years ago
Read 2 more answers
I need help with this
Snezhnost [94]

Answer:

y = - \frac{1}{2} x + 4

Step-by-step explanation:

Let us consider two points through which the line passes through

(x_1 , y _ 1 ) = ( 0 , 4 ) \ and \  (x_ 2 , y _ 2 ) = ( 4, 2 )

Step 1 : <em><u>Find slope of the line</u></em>

Slope, m_1 = \frac{rise}{run}  \\\\That \ is \ m_1 \ = \frac{y_2 - y _ 1}{x_2 - x_1}

                  = \frac{2 - 4}{4-0} \\\\=-\frac{2}{4}\\\\= - \frac{1}{2}

Step 2 : <em><u>Find equation of the line.</u></em>

<em><u /></em>(y - y _ 1) = m_ 1 (x - x_1)\\\\( y - 4) = - \frac{1}{2}(x - 0)\\\\y = -\frac{1}{2}x + 4<em><u /></em>

5 0
3 years ago
Slope=-7 ;(4,-30)<br> what is the equation?
notsponge [240]

Answer:

y=-7x -2

Step-by-step explanation:

use formula to find the equation when you know slope and a point

it is: y-y1 = m(x-x1)

plug in values

y-(-30) = -7(x-4)

y+30 = -7x + 28

- 30 from both sides

y = -7x -2

7 0
3 years ago
The 10th term in the sequence is 2560 what is the 11th term in the sequence
joja [24]

Full Question:

The 4th term of a g.p. is 40 and the 10th term in the sequence is 2560, what is the 11th term in the sequence ?

Answer:

the 11 the term is 5120

Step-by-step explanation:

Given

Geometry Progression

4th term = 40

10th term = 2560

Required

11 term.

The nth term of a geometric sequence is calculated as follows

Tₙ = arⁿ⁻¹

For the 4th term, n = 4 and Tₙ = 40

Substitute these in the given formula; this gives

40 = ar⁴⁻¹

40 = ar³. --;; equation 1

For the 10th term, n = 10 and Tₙ = 2560

Substitute these in the given formula; this gives

2560 = ar¹⁰⁻¹

2560 = ar⁹. --;; equation 2

Divide equation 2 by 1. This gives

2560/40 = ar⁹/ar³

64 = r⁹/r³

From laws of indices

64 = r⁹⁻³

64 = r⁶

Find 6th root of both sides

(64)^1/6 = r

r = (2⁶)^1/6

r = 2

Substitute r = 2 in equation 1

40 = ar³. Becomes

40 = a * 2³

40 = a * 8

40 = 8a

Divide both sides by 8

40/8 = 8a/8

5 = a

a = 5.

Now, the 11 term can be solved using Tₙ = arⁿ⁻¹ where n = 11

So,

Tₙ = arⁿ⁻¹ becomes

Tₙ = 5 * 2¹¹⁻¹

Tₙ = 5 * 2¹¹⁻¹

Tₙ = 5 * 2¹⁰

Tₙ = 5 * 1024

Tₙ = 5120.

Henxe, the 11 the term is 5120

5 0
3 years ago
Simplify the expression. Write your answer as a complex number.<br><br> please help
tia_tia [17]
The answer is
=15-8i
8 0
3 years ago
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