1. A=6b<br> 2. A=12b<br> 3. A=(6b)/2<br> 4. A=(6+b)/2

A line passes through (3, 7) and (6, 9). Which equation best represents the line?

lana [24]

Answer:

brainly.com/question/2574086b

Step-by-step explanation:

brainly.com/question/2574086

8 0

3 years ago

Read 2 more answers

Kareem wrote the values shown below.

sweet [91]

Answer: Option 'B' is correct.

Step-by-step explanation:

Since we have given that

[3.2] [2.7] [2.9] [4.8]

Since they are all of greatest integer functions i.e.

f(x) = [x]

It is known as greatest integer function whose value is always less than or equal to 'x'.

So, [3.2]=3

[2.7]=2

[2.9]=2

[4.8]=4

so, we can see that [2.7] and [2.9] is a equivalent pair.

Hence, Option 'B' is correct.

4 0

3 years ago

Read 2 more answers

A rhombus has four 6-inch sides and two 120-degree angles. From one of the vertices of the obtuse angles, the two latitudes are

nikitadnepr [17]

Answer:

Area(A)=Area(C)= $9 in^{2}$

Area(B)= $13.2 in^{2}$

Step-by-step explanation:

We begin with finding the angles a and b that from the drawing attached you can see that a=b.

Now, the sum of the internal angles of a rhomboid is equal to 360 degrees, with that we have:

120+120+a+b=360

240+2a=360

2a=120

a=60=b

Next, in the image you can see that the lines coming from the angle at the top 120 degrees vertex, divide the opposite sides by half, thus making two triangles with one side of 6 in and another of 3 in.

We can say from the drawing as well:

Area(A)+Area(B)+Area(C)=Area(rhomboid)

But, we can also say that Area(A)=Area(C)

So, starting with Area(A)

Area(A)=Area(triangle)= $\frac{b*h}{2}$ = $\frac{6*3}{2}$ = $9 in^{2}$

We can then calculate the area B, a rhomboid, or better, take the Total area of the figure and subtract the area of the two triangles.

Area(B)=Area(rhomboid)-Area(A)-Area(C)

Area(rhomboid)=b*h where b=6in and h is the perpendicular distance from the base to the top.

$h=[tex]6*cos(30)=5.20in$ The 30 degrees come from: 120-30-60=30, since the latitudes split the 120 angle in two equal parts and one that is the half of the obtuse angle.

Area(rhomboid)=5.20*6= $31.2 in^{2}$

Area(B)=Area(rhomboid)-Area(A)-Area(C)= $31.2 in^{2}$ - $9 in^{2}$ - $9 in^{2}$ = $13.2 in^{2}$

3 0

3 years ago

Simplify LaTeX: \Large\frac{-4^{6} \cdot 4^{2}}{4^{4}}

Oksanka [162]

⇨ The value of this <u>simplified expression</u> = -4096/1 or -4096.

To solve this expression, just multiply the power base by how many times indicate the exponent, and then divide the numerator and denominator of the fraction by the same number.

Power or potentiation is a multiplication in equal factors, where there are <em>terms responsible</em> for obtaining the final result. An potency is given by $\large \sf a^{n}.$ The terms of a power are:

Base
Exponent
equal factors
power

✏️ <u>Resolution/Answer</u>:

$\\ \large \sf \dfrac{-4^{6} \cdot 4^{2}}{4^{4}}=\\\\$

Multiply the powers of the numbers at numerator of the fraction, with the base <em>being multiplied by how many times</em> to indicate the exponent.

$\\\large \sf \dfrac{-4^{6} \cdot 4^{2}}{4^{4}}=$