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yuradex [85]
3 years ago
5

URGENT DAWG. The tangent function is undefined for certain values of x. Therefore, the

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
8 0

Answer:

(vertical) asymptotes

Step-by-step explanation:

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Find the limit of the function algebraically lim (x^2 -36 / x+6 ) x ->6
posledela

9514 1404 393

Answer:

  0

Step-by-step explanation:

The function is defined everywhere except at x=-6. The limit value is the function value at that point.

  f(6) = (6^2 -36)/(6 +6) = 0/12 = 0

The limit of the function is 0 as x → 6.

3 0
3 years ago
Julien threw x number of pitches at baseball practice. Jacob threw 1/5 fewer than that
Naily [24]

Answer:

ok so jacob threw 1/5 of x

Step-by-step explanation:

if you say julien threw x and jacob threw 1/5 of that than jacob threw 1/5 of x

5 0
3 years ago
Sketch the region that is common to the graphs of x ≥ 2,
Oliga [24]

a. Find the graph of their common region in the attachment

b. The area of the common region of the graphs is 8 units²

<h3>a. How to sketch the region common to the graphs?</h3>

Since we have x ≥ 2, y ≥ 0, and x + y ≤ 6, we plot each graph separately and find their region of intersection.

  • The graph of x ≥ 2 is the region right of the line x = 2.
  • The graph of y ≥ 0 is the region above the line y = 0 or x-axis.
  • To plot the graph of x + y ≤ 6, we first plot the graph of x + y = 6 ⇒ y = -x + 6. Then the graph of x + y ≤ 6 is the graph of y ≤ - x + 6.

So, the graph of x + y ≤ 6 is the region below the line y = - x + 6

From the graph, the regions intersect at (2, 0), (2, 4) and (6, 0)

Find the graph of their common region in the attachment

<h3>b. The area of the common region</h3>

From the graph, we see that the common region is a right angled triangle with

  • height = 4 units and
  • base = 4 units

So, its area = 1/2 × height × base

= 1/2 × 4 units × 4 units

= 1/2 × 16 units²

= 8 units²

So, the area of the common region of the graphs is 8 units²

Learn more about region common to graphs here:

brainly.com/question/27932405

#SPJ1

6 0
2 years ago
Can someone help me I have two more other questions they are 15 points each I just posted them right now! Thanks so much
nlexa [21]

Answer:

$10 coins: 21

$20 coins: 24

Step-by-step explanation:

heyy me again

So we can create 2 equations where

x = number of $10 coins

y = number of $20 coins:

x + y = 45

10x + 20y = 690

we can move equation 1 around so that we can get a value of x

x = 45 - y

now we can substitute x into the second equation

10(45 - y) + 20y = 690

450 - 10y + 20y = 690

10y = 240

y = 24

Now plug in y back into the first equation

x = 45 - y

x = 45 - 24

x = 21

8 0
3 years ago
A square is folded into half to form a rectangle. the perimeter of the rectangle is 36cm. calculate the area of a square​
zhannawk [14.2K]

Answer:

Let the measure of each side of the square be " x " cm.

then ,

area of square = x²

After we folded the square into a rectangle ,

length of rectangle = x

breadth of rectangle = x/2

perimeter of rectangle = 36 cm

x +  \frac{x}{2}  + x +  \frac{x}{2}  = 36 \\  \\    \frac{2x + x + 2x + x}{2}  = 36 \\  \\   \frac{6x}{2}  = 36 \\  \\ 6x = 36 \times 2 \\  \\ 6x = 72 \\  \\ 6x =  \cancel{\frac{72}{6} } = 12cm

hence ,

side of square = 12 cm

therefore ,

area of square = 12 × 12 = 144 cm²

hope helpful~

8 0
3 years ago
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