Answer:
(i) When a battery is connected inseries to two long parallel wires, the currents in the two wires will be in opposite directions. Due to which a force of repulsion will be acting between them and they are moving further apart.
(ii) When a battery is connected in parallel to two long parallel wires, the currents in the two wires will be in same direction. Due to it, a force of attraction will be acting between them and they are coming closer to each other.
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The y-component of the velocity of the carrion is equal to zero. That being said, the time it takes for the carrion to reach the ground (as close as possible to the fox) can be calculated through the equation,
d = Vot + 0.5gt²
where d is the distance, Vo is initial velocity (in this case, zero), g is the acceleration due to gravity (9.8 m/s²). Substituting the known values,
14 = 0.5(9.8)(t²)
t = 1.69 seconds
Since the horizontal component of the velocity is 1.5 m/s, the distance from the base of the tree to the point where the carrion will fall is equal to,
(1.5 m/s)(1.69 s) = 2.535 m
We add this to the given distance of the fox from the base of the tree to determine the distance of the fox from the carrion.
total distance = 2.535 m + 7 m = 9.535 m
Given that the time it takes for it to travel would only be 1.69 seconds, the speed would then be,
speed = (9.535 m) / (1.69 s) = 5.64 m/s
<em>ANSWER: speed = 5.64 m/s</em>
Answer:
Hey mate.....
Explanation:
This is ur answer....
<em>A human has 4 types of teeth:-</em>
<em>--> 8 Incisors.
</em>
<em>--> 4 Canines.
</em>
<em>--> 8 Premolars.
</em>
<em>--> 12 Molars (including 4 wisdom teeth)</em>
<em></em>
Hope it helps!
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Answer:
The new speed must be
Explanation:
In order for the satellite to be on a stable orbit around the planet, the gravitational attraction must be equal to the centripetal force that keeps the satellite in circular motion:
where G is the gravitational constant, M is the mass of the planet, m is the mass of the satellite, V0 the speed of the satellite at distance R from the center of the planet.
We can re-write V0, the initial satellite speed, by re-arranging the equation:
Now, if we want the satellite to orbit at a distance of 2R, the new tangential speed must be:
Answer:
the runner's average kinetic energy during the run is 476.96 J.
Explanation:
Given;
mass of the runner, m = 85 kg
distance covered by the runner, d = 42.2 km = 42,200 m
time to complete the race, t = 3 hours 30 mins = (3 x 3600s) + (30 x 60s)
= 12,600 s
The speed of the runner, v = d/t
v = 42,200 / 12,600
v = 3.35 m/s
The runner's average kinetic energy during the run is calculated as;
K.E = ¹/₂mv²
K.E = ¹/₂ × 85 × (3.35)²
K.E = 476.96 J
Therefore, the runner's average kinetic energy during the run is 476.96 J.