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schepotkina [342]
3 years ago
11

Which detail in the first text do you better understand because of the details in the second text?

Physics
2 answers:
umka2103 [35]3 years ago
6 0

Answer:

A

Explanation:

I did it in edge and got 100

anzhelika [568]3 years ago
5 0

Answer:

tourette syndrom

Explanation:

in the 2nd they go into detail about tourette syndrome and in the 2nd they dont talk about any of the other options

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Part APart complete Make a chart showing all the possible sets of quantum numbers l and ml for the states of the electron in the
Olin [163]

Answer:

Its c

Explanation: I double checked and got it right on brainly.

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3 years ago
at the surface of a freshwater spring, a manatee with a small amount of air in its lungs is neutrally buoyant. the manatee now d
Bezzdna [24]

At a depth of 10 m, the manatee's neutral buoyancy keeps it at the same level in water as if there were no air inside its lungs. However, because more air is now contained in the manatee's lungs than before it dove, its weight increases by 9.81 kg and therefore it accelerates downwards (due to momentum). This downward acceleration continues until equilibrium is reached and then ceases due to gravity pulling on both objects equally.

As a result, the manatee now becomes negatively buoyant and must rise to compensate.

<h3>What does it mean when something has neutral buoyancy?</h3>

When something has neutral buoyancy, it is not affected by the weight of anything above or below it.

This means that objects with neutral buoyancy will stay in place regardless of how high or low they are located in a liquid medium.

Examples of things with neutral buoyancy include air balloons and swimming caps.

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8 0
1 year ago
If something is traveling at a constant velocity are forces balanced or unbalanced?
lubasha [3.4K]

Answer:

If something is traveling at a constant velocity, then forces are balanced.

Explanation:

If something is traveling at a constant velocity, then the forces must be balanced because a constant velocity is only achieved with balanced forces.

<em>Please </em><em>like </em><em>and </em><em>mark </em><em>brainliest</em><em>!</em><em> </em>

<em>Hope </em><em>it </em><em>helps!</em>

7 0
4 years ago
Read 2 more answers
I need both parts please (a) Given a material with an attenuation coefficient (a) of 0.6/cm, what is the intensity of a beam (wi
Masteriza [31]

Answer:

<h3>a.</h3>
  • After it has traveled through 1 cm : I(1 \ cm) = 0.5488 I_0
  • After it has traveled through 2 cm : I(2 \ cm) = 0.3012 I_0
<h3>b.</h3>
  • After it has traveled through 1 cm : od( 1\ cm) =  0.2606
  • After it has traveled through 2 cm :  od( 2\ cm) =  0.5211

Explanation:

<h2>a.</h2>

For this problem, we can use the Beer-Lambert law. For constant attenuation coefficient \mu the formula is:

I(x) = I_0 e^{-\mu x}

where I is the intensity of the beam, I_0 is the incident intensity and x is the length of the material traveled.

For our problem, after travelling 1 cm:

I(1 \ cm) = I_0 e^{- 0.6 \frac{1}{cm} \ 1 cm}

I(1 \ cm) = I_0 e^{- 0.6}

I(1 \ cm) = I_0 e^{- 0.6}

I(1 \ cm) = 0.5488 \ I_0

After travelling 2 cm:

I(2 \ cm) = I_0 e^{- 0.6 \frac{1}{cm} \ 2 cm}

I(2 \ cm) = I_0 e^{- 1.2}

I(2 \ cm) = I_0 e^{- 1.2}

I(2 \ cm) = 0.3012 \ I_0

<h2>b</h2>

The optical density od is given by:

od(x) = - log_{10} ( \frac{I(x)}{I_0} ).

So, after travelling 1 cm:

od( 1\ cm) = - log_{10} ( \frac{0.5488 \ I_0}{I_0} )

od( 1\ cm) = - log_{10} ( 0.5488 )

od( 1\ cm) = - (  - 0.2606)

od( 1\ cm) =  0.2606

After travelling 2 cm:

od( 2\ cm) = - log_{10} ( \frac{0.3012 \ I_0}{I_0} )

od( 2\ cm) = - log_{10} ( 0.3012 )

od( 2\ cm) = - (  - 0.5211)

od( 2\ cm) =  0.5211

3 0
3 years ago
An 81 kg football player moving 6.5 m/s tackles and collides with a stationary 140 kg football player. What speed will the footb
Flura [38]
The answer would be 2.4m/s


3 0
4 years ago
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