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3 years ago

Which detail in the first text do you better understand because of the details in the second text?

Physics

2 answers:

umka2103 [35]3 years ago

6 0

Answer:

Explanation:

I did it in edge and got 100

anzhelika [568]3 years ago

5 0

Answer:

tourette syndrom

Explanation:

in the 2nd they go into detail about tourette syndrome and in the 2nd they dont talk about any of the other options

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A weightlifter curls a 30 kg bar, raising it each time a distance of 0.50 m .How many times must he repeat this exercise to burn

ludmilkaskok [199]

Answer:

$N = 2141 times$

Explanation:

Each time the work done to raise a given mass is

$W = mgh$

here we know that

$m = 30 kg$

$h = 0.50 m$

now we have

$W = (30 kg)(9.81 m/s^2)(0.50)$

$W = 147.15 J$

since it is just 25% of actual energy consumed as we know its efficiency is 25%

so we have total energy consumed in this way

$E_{total} = \frac{147.15}{0.25}$

$E_{total} = 588.6 J$

now if it took N number of times so burn the fat of a pizza then

$N(588.6) = 1260 \times 10^3$

$N = 2141 times$

4 0

3 years ago

An air track car with a mass of 0.75 kg and a velocity of 8.5 m/s to the right collides elastically with a 0.65kg car moving to

Sunny_sXe [5.5K]

We can do this with the conservation of momentum. The fact it is elastic means no KE is lost so we don't have to worry about the loss due to sound energy etc.

Firstly, let's calculate the momentum of both objects using p=mv:

Object 1:
p = 0.75 x 8.5 = 6.375 kgm/s

Object 2 (we will make this one negative as it is travelling in the opposite direction):
p = 0.65 x -(7.2) = -4.68 kgm/s

Based on this we know that the momentum is going to be in the direction of object one, and will be 6.375-4.68=1.695 kgm/s

Substituting this into p=mv again:

1.695 = (0.75+0.65) x v
Note I assume here the objects stick together, it doesn't specify - it should!

1.695 = 1.4v
v=1.695/1.4 = 1.2 m/s to the right (to 2sf)

8 0

3 years ago

You select a rental package that includes a car with an average consumption of 6.00 liters of fuel per 100 km. Considering that

konstantin123 [22]

7.21 USD.

<h3>Further explanation</h3>

<u>Problem:</u>

Given in Europe, the average fuel cost is 1.063 euros/liter.
A car with an average consumption of 6.00 liters of fuel per 100 km.

<u>Question: </u>

How much (in US dollars) will we spend properly on fuel on our trip? Express the answer numerically in US dollars to three significant figures.

Let us convert the unit price from the euro to USD. Currently, the exchange rate of 1 euro is 1.13 USD.

$\boxed{ \ 1.063 \ euro \times \frac{1.13 \ USD}{1 \ euro} = 1.20119 \ USD \ }$

The term euro is crossed out.

After currency conversion, the average fuel cost is 1.20119 USD/liter.

We need 6.00 liters of fuel during the trip.

$\boxed{ \ 6.00 \ liters \times \frac{1.20119 \ USD}{1 \ liter} = 7.20714 \ USD \ }$

The term liter is crossed out.

We rounded up to three significant figures. Hence, the cost that we will spend on fuel on our trip is as much $\boxed{\boxed{ \ 7.21 \ USD \ }}$

<em>Want to follow another way? Let's see.</em>

$\boxed{ \ 6.00 \ liters \times \frac{1.063 \ euros}{1 \ liter} = 6.378 \ euro \ }$

The term liter is crossed out.

$\boxed{ \ 6.378 \ euro \times \frac{1.13 \ USD}{1 \ euro} = 7.20714 \ USD \ }$

The term euro is crossed out.

We get a similar result, i.e.,

$\boxed{\boxed{ \ 7.21 \ USD \ }}$

<h3>Learn more</h3>

The unit conversion factor from cubic-centimeters to cubic-inches brainly.com/question/5009365
How to write in scientific notation brainly.com/question/7263463
Calculating mass based on density and volume brainly.com/question/4053884

Keywords: you select, a rental package, a car with average consumption, 6.00 liters of fuel per 100 km, in Europe, the cost is 1.063 euros/liter, how much, in US dollars, USD, spend, trip, express, numerically, three significant figures, conversion

7 0

4 years ago

Read 2 more answers

Two balls with equal masses, m, and equal speed, v, engage in a head on elastic collision. what is the final velocity of each ba

Allushta [10]

The collision is elastic. This means that both momentum and kinetic energy are conserved after the collision.

- Let's start with conservation of momentum. The initial momentum of the total system is the sum of the momenta of the two balls, but we should put a negative sign in front of the velocity of the second ball, because it travels in the opposite direction of ball 1. So ball 1 has mass m and speed v, while ball 2 has mass m and speed -v:
$p_i = p_1-p_2 = mv-mv =0$
So, the final momentum must be zero as well:
$p_f = 0$
Calling v1 and v2 the velocities of the two balls after the collision, the final momentum can be written as
$p_f = mv_1 + mv_2 = 0$
From which
$v_1 = -v_2$

- So now let's apply conservation of kinetic energy. The kinetic energy of each ball is $\frac{1}{2} mv^2$ . Therefore, the total kinetic energy before the collision is
$K_i = \frac{1}{2} mv^2 + \frac{1}{2} mv^2 = mv^2$
the kinetic energy after the collision must be conserved, and therefore must be equal to this value:
$K_f = K_i = mv^2$ (1)
But the final kinetic energy, Kf, is also
$K_f = \frac{1}{2} mv_1^2 + \frac{1}{2}mv_2^2$
Substituting $v_1 = -v_2$ as we found in the conservation of momentum, this becomes
$K_f = mv_2 ^2$
we also said that Kf must be equal to the initial kinetic energy (1), therefore we can write
$mv_2^2 = mv^2$

Therefore, the two final speeds of the balls are
$v_2 = v$
$v_1 = -v_2 = -v$

This means that after the collision, the two balls have same velocity v, but they go in the opposite direction with respect to their original direction.

8 0

3 years ago

Please please answer this! explain the kinetic molecular theory ( i don't understand how they explain it in my lesson so if some

Bess [88]

Answer:

Explanation:

Basically, Kinetic Molecular Theory says that gas particles are in constant motion and that they show perfectly elastic collisions.

An elastic collision is a collision in which there is no net loss in kinetic energy in the system as a result of the collision.

So the kinetic molecular theory says that gas particles stay moving constantly and don't lose energy when they run into each other.

Hope this helps!

4 0

3 years ago