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Nikolay [14]
3 years ago
9

A ball is kicked from a height of 20 meters above the ground. If the initial velocity is 10 m/s, how long is the ball in flight

before striking the ground?
Physics
1 answer:
nasty-shy [4]3 years ago
8 0
S=20 m
v=10 m/s
t=s/v
= 20/10
= 2 s.
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You solve for l in the equation (1):

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T'=2\pi \sqrt{\frac{l}{g'}}\\\\g'=\frac{4\pi^2l}{T'^2}

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g'=\frac{4\pi^2(0.35m)}{(1.18s)^2}=10.12\frac{m}{s^2}

The acceleration due to gravity at the top of the mountain is 10.12m/s^2

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