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3 years ago

Let f(x)=10x-10 find the value of (f o f ^-1)(-10)

Mathematics

1 answer:

polet [3.4K]3 years ago

6 0

Answer:

Step-by-step explanation:

let y=f(x)

y=10x-10

flip x and y

x=10y-10

10 y=x+10

$y=\frac{1}{10}x+1\\f^{-1}(x)=\frac{1}{10}x+1\\(fof^{-1}{x})=f(f^{-1}(x))=f(\frac{1}{10} x+1)=10(\frac{1}{10} x+1)-10=x+10-10=x\\(fof^{-1})(-10)=-10$

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LekaFEV [45]

Answer:

A≈254.47ft²

Step-by-step explanation:

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7 0

2 years ago

Add: (-3p6 + 5) + 9p6

timama [110]

Answer:

6p^6+ 5

Step-by-step explanation:

Step by step solution :

Step 1 :

Equation at the end of step 1 :

((0 - (3 • (p6))) + 5) + 32p6

Step 2 :

Equation at the end of step 2 :

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Step 3 :

Trying to factor as a Sum of Cubes :

3.1 Factoring: 6p6+5

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2 years ago

List the sets that -6 belongs to: whole numbers, integers, rational numbers, irrational numbers, and real numbers.

goldfiish [28.3K]

Answer:

Whole Number : 6

Integers: -6 and 6

Rational Number: -6.0 and -6/1

Irrational Number: -Infinity or -0

8 0

3 years ago

A circle is shown. 2 raddi are drawn. A chord connects the points of the radii on the circle to each other to form a triangle. T

iragen [17]

Answer:

$(5\pi-11.6)ft^2$

Step-by-step explanation:

Given:

Length of radius of circle = 5 feets

Length of perpendicular bisector = 4 feets

To find:

Area of the shaded portion of the circle

Solution:

As OD is perpendicular bisector of AB,

$AB=2AD=2(2.9)=5.8\,\,feets$

$\angle ODA=90^{\circ}$

Area of $\Delta AOB$ = 1/2 (base) × (height) = $\frac{1}{2}\times 4\times 5.8=11.6$ square feets

Area of sector AOBC = $\frac{\angle AOB}{360^{\circ}}\pi(r^2)=\frac{72^{\circ}}{360^{\circ}}\pi(5^2)=5\pi$ square feets

Here, r denotes radius of circle

So,

Area of shaded portion = Area of sector AOBC - Area of $\Delta AOB$ = $(5\pi-11.6)ft^2$

Download pptx

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2 years ago

Which statements are true about the circle shown below? Select two options. A circle with radius 31.4 centimeters. The diameter

Advocard [28]

C,D

Step-by-step explanation:

E d g e n u i t y

6 0

3 years ago