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3 years ago

Let f(x)=10x-10 find the value of (f o f ^-1)(-10)

Mathematics

1 answer:

polet [3.4K]3 years ago

6 0

Answer:

Step-by-step explanation:

let y=f(x)

y=10x-10

flip x and y

x=10y-10

10 y=x+10

$y=\frac{1}{10}x+1\\f^{-1}(x)=\frac{1}{10}x+1\\(fof^{-1}{x})=f(f^{-1}(x))=f(\frac{1}{10} x+1)=10(\frac{1}{10} x+1)-10=x+10-10=x\\(fof^{-1})(-10)=-10$

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3 years ago

Consider the two expressions 4b(b+1) and (2b+7)(2b-8). Compare their values if b=-3, b=-2, and if b=10. Is it true that for an v

frutty [35]

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FIRST EXPRESSION:

- If $b=-3$ , the value of $4b(b+1)$ is $24$

- If $b=-2$ , the value of $4b(b+1)$ is $8$

- If $b=10$ , the value of $4b(b+1)$ is $440$

SECOND EXPRESSION:

- If $b=-3$ , the value of $(2b+7)(2b-8))$ is $-14$

- If $b=-2$ , the value of $(2b+7)(2b-8))$ is $-36$

- If $b=10$ , the value of $(2b+7)(2b-8))$ is $324$

Yes, for any value of "b" the value of the first expression is greater than the value of the second expression.

Step-by-step explanation:

Substitute the given values of "b" into each expression and evaluate.

- For the first expression $4b(b+1)$ , you get:

If $b=-3$ → $4(-3)(-3+1)=24$

If $b=-2$ → $4(-2)(-2+1)=8$

If $b=10$ → $4(10)(10+1)=440$

- For the second expression $(2b+7)(2b-8))$ , you get:

If $b=-3$ → $(2(-3)+7)(2(-3)-8)=-14$

If $b=-2$ → $(2(-2)+7)(2(-2)-8)=-36$

If $b=10$ → $(2(10)+7)(2(10)-8)=324$

You can observe that for any value of "b" the value of the first expression is greater than the value of the second expression.

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