I need to complete the equation of the line through (-10 3) and (-8 -8). Thanks in advance!
1 answer:
Equation for line is given by,
(y-y1) = ((y2-y1)/(x2-x1)) * (x-x1)
Hence, y-3 = ((-8-3)/(-8+10)) * (x+10)
y-3 = (-11/2) * (x+10)
2y-6 = -11x -110
11x + 2y + 104 = 0 is the equation of the line.
Hope it helps!
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