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dalvyx [7]
3 years ago
13

The area of this circle is 72π m². What is the area of a 45º sector of this circle?

Mathematics
2 answers:
DENIUS [597]3 years ago
6 0

Answer:

9 \pi m^2

Step-by-step explanation:

Given that there is a circle whose area is 72pi m^2

Area of a circle = \pi r^2 =72\pi\\

We are to find the area of a sector with angle 45 degrees

We have formula for area of sector as

Area of sector = central angle* area of circle/360

Substitute the known values to get

Area of sector = \frac{45}{360} (72\pi) = 9 \pi m^2

Hence we get

area of sector with 45 degrees = 9 \pi m^2

Leviafan [203]3 years ago
3 0

This angle is 45°. That is 1/8 of a whole turn (360°)

So the arc is 1/8 of the circumference.

And the sector area is 1/8 of the area of the circle.

So the area of the sector is 28.27 m²

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You are searching for two integers. The sum of twice the first integer and three times the second integer is nine. At the same t
devlian [24]

Answer:  -3 and 5

<u>Step-by-step explanation:</u>

Let x represent the 1st digit and y represent the 2nd digit. Then,

Eq 1: 2x + 3y = 9   →    3(2x + 3y = 9)     →     6x + 9y = 27

Eq 2: 3x + 2y = 1   →   -2(3x + 2y = 1)     →     <u>-6x - 4y =  -2</u>

                                                                              5y = 25

                                                                                y =  5

Substitute y = 5 into either of the original equations to solve for x:

2x + 3y = 9

2x + 3(5) = 9

2x + 15 = 9

2x        = -6

 x        = -3

Check (using the other original equation):

3x + 2y = 1

3(-3) + 2(5) = 1

-9    +  10   = 1

        -1       = 1  \checkmark

4 0
3 years ago
Keegan jogs laps around a park playground. The playground is 90m long and 35m wide. How many laps will it take him to jog 1 km?
VMariaS [17]
It will take 3 laps. 90*35=3150 1000 m = 1 km
8 0
3 years ago
The sun produces 3.9 ⋅ 10 to the 33th power ergs of radiant energy per second. How many ergs of radiant energy does the sun prod
arlik [135]
So the sun produces 3.9x10³³/ second

Using this ratio (3.9x10³³/ second) we can use the porpotions to calculate time taken (T) to produce 1.55x10⁷.

\frac{3.9(10^3) ergs}{1 second} =  \frac{1.55(10^7)ergs}{T}

Then isolate T and find the time

\frac{T3.9(10^3)ergs}{1 second} = {1.55(10^7)ergs
T3.9(10^3)ergs = ({1.55(10^7)ergs)seconds
T =  \frac{(1.55(10^7)ergs)seconds}{3.9(10^3)ergs}
T =  \frac{(1.55(10^7)seconds}{3.9(10^3)}
T = \frac{1.55}{3.9}(10^4)seconds
T = 0.397(10^4)seconds
T = 3.97(10^-^1)(10^4)seconds
T = 3.97(10^3)seconds

Thus it took 3.97x10³ seconds for 1.55x10⁷. of ergs to be produced
Hope that helped and if it did, a Brainliest rating would be much appreciated


6 0
3 years ago
An open box is formed from a rectangular piece of cardboard whose length is 8cm more than its width by cutting squares of 2cm fr
Serggg [28]
If the width of the cardboard = x cm then its length is given by x + 8 cm.
Then the length of the box will be x + 8 - 2(2) =  x + 4
and the width = x - 2(2) = x - 4 cm The height is 2 cm 

Volume = h*w*l = 2(x - 4)(x + 4) = 256
2(x^2 - 16) = 256
x^2 - 16 = 128
x^2  = 144 
x = 12 cm 

Dimensions of the box are:-

length =  12 + 4 =  16cm
width = 12 - 4 = 8 cm
height = 2 cm



















3 0
3 years ago
The graph of F(x), shown below, has the same shape as the graph of G(X) =
defon

Answer: (X-3)^4

Step-by-step explanation:

To shift a function left, add inside the function's argument: f (x + b) gives f (x)shifted b units to the left. Shifting to the right works the same way; f (x – b) is f (x) shifted b units to the right.

Therefore, the equation is F(x) = G(x-3) = (X-3)^4

7 0
3 years ago
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