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vivado [14]
2 years ago
10

Q25 A train travelling at a speed of 30km/h crosses a bridge 25m long in 12 sec. How long will it take to overtake a another tra

in 25m long travelling at 20km/hr? ​option given 1. 72 sec 2. 74 sec 3. ,75 sec or data insufficient.
Mathematics
1 answer:
Makovka662 [10]2 years ago
8 0

Answer:

WHAT

Step-by-step explanation:

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-30 + 10<br> Find the sum
ludmilkaskok [199]
The answer of -30+10 is -20

-30+10=-20
5 0
3 years ago
Please help thank you
Shkiper50 [21]

Answer:

x = 0.25

Step-by-step explanation:

When logs are added together, they are actually multiplied and then the logs taken of the product.

That sentence is actually correct, but you are going to have to read it a couple of times. You might understand it if I actually just solve the problem.

ln(2x) + ln(2) = 0              Combine the two subjects to make 1 ln.

ln (2)(2x) = 0                    Now take the antilog

ln(4x) = 0

antilog ln(4x) = e^0         e^0 = 1

4x = 1                                See your last problem.

x = 1/4

Now the question is "What's the answer?" It might be 1/4 but I doubt it. A better choice would be x = 1/4 or x = 0.25

I'd try the last one first.

6 0
3 years ago
Can you help with a please on 46
valentina_108 [34]
3/5
Thats if u devide 9 by 3 and 15 by 5
5 0
3 years ago
Read 2 more answers
The local swim team is considering offering a new semi-private class aimed at entry-level swimmers, but needs a minimum number o
SCORPION-xisa [38]

Answer:

The significance level is \alpha=0.01 and since we are conducting a right tailed test we need to find a critical value who accumulate 0.01 of the area in the right of the normal standard distribution and we got:

z_{\alpha/2}= 2.326

So we reject the null hypothesis is z>2.326

Step-by-step explanation:

For this case we define the random variable X as the number of entry-level swimmers and we are interested about the true population mean for this variable . On specific we want to test this:

Null hypothesis: \mu \leq 15

Alternative hypothesis: \mu > 15

And the statistic is given by:

z =\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

The significance level is \alpha=0.01 and since we are conducting a right tailed test we need to find a critical value who accumulate 0.01 of the area in the right of the normal standard distribution and we got:

z_{\alpha/2}= 2.326

So we reject the null hypothesis is z>2.326

7 0
3 years ago
It costs $3.55 to make a sandwich at the local deli shop. To make a profit, the deli sells it at a price that is 160% of the cos
larisa [96]
Okay this is what i got it might be wrong but i did it and then looked it up to make sure i was right & it showed the same answer!!

3.55 * 1.6= 5.68!!
4 0
3 years ago
Read 2 more answers
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