Answer: im so confused
Step-by-step explanation:
Answer:
Step-by-step explanation:
given a point the equation of a line with slope m that passes through the given point is
or equivalently
.
Recall that a line of the form , the y intercept is b and the x intercept is .
So, in our case, the y intercept is and the x intercept is .
In our case, we know that the line is tangent to the graph of 1/x. So consider a point over the graph . Which means that
The slope of the tangent line is given by the derivative of the function evaluated at . Using the properties of derivatives, we get
. So evaluated at we get
Replacing the values in our previous findings we get that the y intercept is
The x intercept is
The triangle in consideration has height and base . So the area is
So regardless of the point we take on the graph, the area of the triangle is always 2.
Including Jamiz, there are 14 girls in the class. If this if half of the total number of pupils (as half are girls, the other half being boys) the total number of students is 14 × 2 = 28 students
Answer:
Step-by-step explanation:
As X is an acute angle, all 6 trigonometric functions with an argument of X are positive.
Using the identity ,
Answer:
3.33 and 1/3
Step-by-step explanation:
"Dense" here means that there are infinite irrational numbers between two rational numbers. Also, there are infinite rational numbers between two rational numbers. That's the meaning of dense. Actually, that can be apply to all real numbers, there always is gonna be a number between other two.
But, to demonstrate that irrationals are dense, we have to based on an interval with rational limits, because the theorem about dense sets is about rationals, and the dense irrational set is a deduction from it. That's why the best option is 2, because that's an interval with rational limits.