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2 years ago

5

mike made 5 fewer than three times the number of bracelets that sheri made. Write an expression to represent the number of brack

ets mike made. then determine the number of bracelets that mike made if sheri made 12 bracelets

1 answer:

jenyasd209 [6]2 years ago

3 0

Answer:

the answers are in the pic

Step-by-step explanation:

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Which two sentences indicate a first-person point of view? 1 Shelley, our cat, always gets excited when Mrs. Peters visits us. 2

irga5000 [103]

The two sentences are 1 and 5.

3 0

3 years ago

Porfabor necesito ayuda en la esta pregunta. ¿Encuentra cuatro pares ordenados de la siguiente función? f(x) = X3 – 2X2 – 2

zlopas [31]

Answer:

(0, -2), (1, -3), (2, -2) y (3, 7) son pares ordenados de $f(x) = x^{3}-2\cdot x^{2}-2$ .

Step-by-step explanation:

Un par ordenado es un elemento de la forma $(x,f(x))$ , donde $x$ es un elemento del dominio de la función, mientras $f(x)$ es la imagen de la función evaluada en $x$ . Entonces, un par ordenado que está contenido en la citada función debe satisfacer la siguiente condición:

La imagen de la función existe para un elemento dado del dominio. Esto es:

$x \rightarrow f(x)$

Dado que $f(x)$ es una función polinómica, existe una imagen para todo elemento $x$ . Ahora, se eligen elementos arbitrarios del dominio para determinar sus imágenes respectivas:

x = 0

$f(0) = 0^{3}-2\cdot (0)^{2}-2$

$f(0) = -2$

(0, -2) es un par ordenado de $f(x) = x^{3}-2\cdot x^{2}-2$ .

x = 1

$f(1) = 1^{3}-2\cdot (1)^{2}-2$

$f(1) = -3$

(1, -3) es un par ordenado de $f(x) = x^{3}-2\cdot x^{2}-2$ .

x = 2

$f(2) = 2^{3}-2\cdot (2)^{2}-2$

$f(2) = -2$

(2, -2) es un par ordenado de $f(x) = x^{3}-2\cdot x^{2}-2$ .

x = 3

$f(3) = 3^{3}-2\cdot (3)^{2}-2$

$f(3) = 7$

(3, 7) es un par ordenado de $f(x) = x^{3}-2\cdot x^{2}-2$ .

(0, -2), (1, -3), (2, -2) y (3, 7) son pares ordenados de $f(x) = x^{3}-2\cdot x^{2}-2$ .

6 0

2 years ago

What is 57/100 in the simplest form

DerKrebs [107]

Answer: 57%

Step-by-step explanation:

3 0

3 years ago

An object launched straight up at a speed of 29.4 meters per second has a height, h, in meters of h , t seconds after the object

Nostrana [21]

Answer:

h = 44.06 meters (maximum height)

the time the object takes to complete this whole path is 6 seconds, this is why the time at which the object reaches its maximum height will between 0 and 6 seconds

Step-by-step explanation:

To solve this question, we need to first recognize that this is a constant acceleration problem, specifically, it can be thought of as a projectile motion problem.

Recall, the equations of motion:

$1) v^2 - v_0^2 = 2a(s - s_0)\\2) s = v_0^2 + \frac{1}{2} at^2\\3) v = v_0 + at$

What do we already know?

$v_0 = 29.4 ms^-1$
The launch is straight up
$a = -9.81 ms^-2$ this is the gravitational acceleration $g$

$s_0 = 0 m$ , since our reference point is at s = 0, (the ground)

We can use use the Eq(1):

we know that when any object is launched up, at maximum height its velocity is going to be zero, $v = 0 ms^-2$

$v^2 - v_0^2 = 2a(s - s_0)\\0^2 - (29.4)^2 = 2(-9.81)(s- 0)\\s = 44.06 m$

this is the maximum height!

Why does t have to between zero and six?

We can answer this using a bit visualization, if you think about the second equation

$s = v_0 t - \frac{1}{2}at^2\\ s = 29.4t - 4.905t^2$

this is the equation of the whole trajectory that object makes.

and if you solve this by making $s = 0$ , you will get the times at which the object was at the ground. the times will be 0s and 5.99s.

so the amount of time the object takes to go through this whole path is 6 seconds and this why the object will only reach its maximum height in between this time interval.

hope this helps :)

5 0

3 years ago

Can someone explain the formula for the area of a pentagon, and the formula for the length of an arc of a portion of a circle? P

RSB [31]

So a pentagon is constructed by five identical triangles, that's why you can find the area of one triangle and multiply it with 5:
A_pentagon=A_triangle*5
To find the area of a triangle you must use tangens.
You can watch this for more on that on youtube.

For the length of an arc or a portion of a circle you can find it using:
arc lenght = 2π*r(A/360), where A=angle.
So if you know radians, then 2π is a whole circle. And to calculate for the specific circle you have to use the radius. That's why you multiply with radius, which is the only difference between any two different circles. you then multiply with the part of the circle that you want to find the lenght for, which is A/360 (because there are 360° in a circle)

I hope that helped.

4 0

2 years ago