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Lemur [1.5K]
2 years ago
5

Help me please please

Mathematics
1 answer:
Dimas [21]2 years ago
5 0

Sorry i messed up at first i think it actually is 50.3

Step-by-step explanation:

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Bill buys and sells laptops. Last month Bill bought 50 laptops. He paid £400 for each laptop. He sold 40 of these laptops at a p
Ivenika [448]

Answer:

As Bill's sales is £25400, which is greater than £25000, he achieved his target.

Step-by-step explanation:

Cost of each laptop = £400

lets calculate for 40 laptops first

Given, he sold 40 of these at 30% profit

30% of cost price = 30% of  £400  = 30/100 * 400 = 120

Therefore, selling price of these laptops =  £400  +  £120 =  £520

Total sales generated from selling 40 of these laptop = 40*£520

= £520 =£20,800  

lets calculate for 10 laptops now

Given, he sold 10 of these at 15% profit

15% of cost price = 15% of  £400  = 15/100 * 400 = 60

Therefore, selling price of these laptops =  £400  +  £60 =  £460

Total sales generated from selling 10 of these laptop = 10*£460

= £4600

Total sales generated from selling all the 50 laptop =  

Total sales generated from selling 40 of these laptop + Total, sales generated from selling 10 of these laptop = £20,800  + £4600 = £25,400

Target for Bill = £25000

As his sales is £25400, which is greater than £25000, he achieved his target.

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Given the function f(x) = -2c+cx-x^2, and f^-1(5) = -1, find c
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Answer:

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Step-by-step explanation:

We are given the function:

f(x) = -2c + cx - x^2

And that:

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And we want to determine the value of <em>c</em>.

Recall that by definition of inverse functions:

\displaystyle \text{If } f(a) = b, \text{ then } f^{-1}(b) = a

So, since f⁻¹(5) = -1, then f(-1) = 5.

Substitute:

f(-1) = 5 = -2c + c(-1) - (-1)^2

Simplify:

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Combine like terms:

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And divide. Hence:

c = -2

In conclusion, the value of <em>c</em> is -2.

8 0
3 years ago
The sum of two number is 63the smaller number is 17 less than the larger number.what are the number
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Answer:

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Step-by-step explanation:

Let x be the larger number.

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Hope this helped!

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