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erastovalidia [21]
3 years ago
15

July 15: Hire part-time helper to be paid $12 per hour. Pay periods are the 1st through the 15th and 16th through the end of the

month, with paydays being the 20th for the first pay period and the 5th of the following month for the second pay period. (No entry is required on this date; it is here for informational purposes only.)
Mathematics
1 answer:
nikklg [1K]3 years ago
3 0

Answer:

The information above is just a part of a long question.The main question is  found in the attached as well as the answer following a step by step methodical approach.

Step-by-step explanation:

Take a good at the full question before venturing into the statements prepared so as to have a thorough understanding of the requirements and how the answers provided have touched upon the requirements.

Download xlsx
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Deborah needs fabric for her costume. she buys 3.25 yards of material at $5.87 a yard What is the total cost of the fabric? Roun
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19.08

Step-by-step explanation:

just multiply and round to get 2 decimals

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Solve Algebraically by Factoring.<br> Solve for x. <br> (x – 3)(x – 2) = 0
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Which choice is equivalent to the fraction below when x is greater than or equal to 2?
miss Akunina [59]

Answer:

D. 2(√{x} + √{x - 2})

Step-by-step explanation:

As hinted in the question, we have to simplify the denominator.

To understand it easier, let's imagine we have x - y in the denominator.  If we multiply it with x + y we'll get x² - y², right?  Check the next line:

(x - y) (x + y) = x² + xy -xy - y² = x² - y²

If we have the square of those nasty square roots, it will be much simpler to deal with.  So, let's multiply the initial fraction using x+y, but with the real values:

\frac{4}{\sqrt{x} - \sqrt{x - 2} } * \frac{\sqrt{x} + \sqrt{x - 2}}{\sqrt{x} - \sqrt{x - 2}} = \frac{4(\sqrt{x} + \sqrt{x - 2})}{(\sqrt{x} )^{2} - (\sqrt{x - 2} )^{2} }

Then we simplify:

\frac{4(\sqrt{x} + \sqrt{x - 2})}{(\sqrt{x} )^{2} - (\sqrt{x - 2} )^{2} } = \frac{4(\sqrt{x} + \sqrt{x - 2})}{(x) - (x - 2) } = \frac{4(\sqrt{x} + \sqrt{x - 2})}{ 2 } = 2(\sqrt{x} + \sqrt{x - 2})

Answer is D. 2(√{x} + √{x - 2})

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3 years ago
enter decimal numbers in the boxes to complete the order pair that locates point Q on the coordinate plane
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Q would equal (1.5,-1.5)
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