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Aneli [31]
3 years ago
11

The 150 students in the marching band and 30 of them play the trumpet. which number line represents the percent of the student i

n the marching band who play the trumpet ?
Mathematics
1 answer:
photoshop1234 [79]3 years ago
7 0

Answer: 20%

Step-by-step explanation:

The 150 students in the marching band and 30 of the students play the trumpet. To get the percentage of students that play the trumpet, we divide 30 by 150 and then multiply by 100. This can be written as:

= 30/150 × 100

= 0.2 × 100

= 20%

The percentage of students that play the trumpet is 20%

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The measure of 6
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A human brain weighs about 1 kg and contains about 1011 cells. Assuming that each cell is completely filled with water (density
elena-s [515]

Answer:

Step-by-step explanation:

From the information given:

a human brain weighs = 1 kg ; = 1000 grams

Number of cells = 10¹¹ cells

The density of water filled in each cell = 1 g/mL

From above;

the weight of each of the brain cell = total weight of the human brain/the number of cells

the weight of each of the brain cell = 1000/10¹¹

the weight of each of the brain cell = 1 × 10⁻⁸ grams

Now, to calculate the quantity of water in each cell; we have:

= the weight of each brain × density

= 1 \times 10^{-8} \ g \times \dfrac{1 \ mL}{1   \ g}= 1 \times 10^{-8} \ mL

For cube; we know that

1 mL = 1 cm³

Thus:

1 \times 10^{-8} \ mL=  1 \times 10^{-8} \ cm^3

Recall that; the volume of a cube as well = x^3

where;

x = length of each sides

∴

x^3 = 1 \times 10^{-8} \ cm^3

x = \sqrt[3]{1 \times 10^{-8}}

x = 0.0022 cm

Thus, the length of each side of the cell = 0.0022 cm

The surface area of a single cell = x²

The surface area of a single cell = (0.0022 cm)²

The surface area of a single cell = 4.84 × 10⁻⁶ cm²

Therefore, the total surface area of  is:

1 \times 10^{11}  \ cells \times \dfrac{4.84 * 10^{-6} \ cm^2}{1 \ cell}

= 4.84 \times 10^5 cm^2

= 5.0\times 10^5 cm^2

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7 0
4 years ago
If we list all the natural numbers below 20 that are multiples of 7 or 11, we get 7, 11 and 14. The sum of these multiples is 32
velikii [3]
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Number of multiples of 11 up to 1337: \left\lfloor\dfrac{1337}{11}\right\rfloor=121
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This means there are 191+121-17=295 distinct multiples of 7 *or* 11 up to 1337.

The sum of these multiples is

\displaystyle\sum_{k=1}^{191}7k+\sum_{k=1}^{121}11k-\sum_{k=1}^{17}77k

which can be computed using the well-known formula,

\displaystyle\sum_{k=1}^nk=\dfrac{n(n+1)}2

So you have

\displaystyle\sum_{k=1}^{191}7k+\sum_{k=1}^{121}11k-\sum_{k=1}^{17}77k=7\dfrac{191\times192}2+11\dfrac{121\times122}2-77\dfrac{17\times18}2=197762
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3 years ago
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Answer:

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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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