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irga5000 [103]
2 years ago
12

The Empire State Building is 1,454 feet tall, and its antenna spire accounts for

Mathematics
1 answer:
sleet_krkn [62]2 years ago
3 0

The value of k is 735 feet.

<h3>What is a scale drawing? </h3>

A scale drawing is a smaller image in terms of dimensions of a bigger image / building / object.

The scale of the drawing = original dimensions / dimensions of the scale drawing

<h3>What is the value of k? </h3>

The value of k = height of the antenna / length of the antenna in the model

750 / 1..02 = 735 feet

To learn more about scale drawings, please check: brainly.com/question/980463

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Solve X/3 - 2X+1/3 = X-3/5​
iren2701 [21]

Answer:

Answer is 3

Step-by-step explanation:

x/3-2x/1+3 =x-3/5

x/3-x/3 = x-3/5

0=x-3/5

0=x-3

3=x

sothat, x = 3 ans

3 0
2 years ago
Pyramids and cones have how many base
Blababa [14]

Answer:

pyramids and cones have 1 base.

Step-by-step explanation:

4 0
2 years ago
The sum of the first n terms of an arithmetic sequence is n/2(4n + 20).
lesantik [10]

Answer:

(a).

S_{n} =  \frac{n}{2} (4n + 20) \\  \\S _{n - 1} =  \frac{(n - 1)}{2} (4n - 4 + 20) \\  \\ S _{n - 1} =  \frac{(n - 1)}{2} (4n + 16) \\  \\S _{n - 1} = \frac{(n - 1)(4n + 16)}{2}  \\   \\  { \boxed{S _{n - 1} =  {2 {n}^{2} + 6n - 8}}} \\

(b).

from general equation:

S _{n - 1} =  \frac{(n - 1)}{2} (4n + 16)

first term is 4n

common difference:

16 =  \{(n - 1) - 1 \}d \\ 16 = (n - 2)d \\ d =  \frac{16}{n - 2}

8 0
3 years ago
skew-symmetric 3 x 3 matrices form as subspace of all 3 x 3 matrices and find a basis for this subspace.
Neporo4naja [7]

Answer:

a) ∝A ∈ W

so by subspace, W is subspace of 3 × 3 matrix

b) therefore Basis of W is

={ {\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]}

Step-by-step explanation:

Given the data in the question;

W = { A| Air Skew symmetric matrix}

= {A | A = -A^T }

A ; O⁻ = -O⁻^T        O⁻ : Zero mstrix

O⁻ ∈ W

now let A, B ∈ W

A = -A^T       B = -B^T

(A+B)^T = A^T + B^T

= -A - B

- ( A + B )

⇒ A + B = -( A + B)^T

∴ A + B ∈ W.

∝ ∈ | R

(∝.A)^T = ∝A^T

= ∝( -A)

= -( ∝A)

(∝A) = -( ∝A)^T

∴ ∝A ∈ W

so by subspace, W is subspace of 3 × 3 matrix

A ∈ W

A = -AT

A = \left[\begin{array}{ccc}o&a&b\\-a&o&c\\-b&-c&0\end{array}\right]

= a\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right] +b\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right] +c\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]

therefore Basis of W is

={ {\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]}

8 0
3 years ago
Subtract 1/4w+4 from 1/2w+3.<br><br> A. −14w+7<br><br> B. −14w+1<br><br> C. 14w+7<br><br> D. 14w−1
frozen [14]
Im going with B) -14w+1
3 0
3 years ago
Read 2 more answers
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