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3 years ago

6

A combination lock requires 4 selections of numbers, each from 1 to 20. • how many different combinations are there? • suppose t

hat the lock is constructed in such a way that no number maybe used twice. how many different combinations are possible?

1 answer:

slamgirl [31]3 years ago

6 0

NUmber of combination = 20 x 19 x 18 x 17 = 116 280

Answer: 116 280

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Missing part of question:

Draw a tape diagram to show how much cake each of the five children received.

Answer:

See attachment

Step-by-step explanation:

Given

$Equal\ Pieces = 6$

$Children = 5$

Required

Tape diagram to represent the scenario

Because one child is not hungry, the number of children to share the cake becomes 6.

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$Share = \frac{6}{5}$

$Share = 1.2$

See attachment for tape diagram

The tape diagram implies that:

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or

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