Answer: n = 600.25 ≈ 601 ( sample size)
the minimum sample size of the adults in United State who have sleep deprivation is 601
Step-by-step explanation:
Given that;
the confidence level = 95% = 0.05
the Margin of error E = 4% = 0.04
∴ level of significance ∝ = 1 - C.L
∝ = 1 - (95/100)
= 0.05
Z∝/2 = 0.05/2 = 0.025
Z-critical value at 95% confidence level is OR level of significance at 0.025 = 1.96 (z-table)
Now to calculate the sample size, we say
n = (Z(critical) / M.E )² P ( 1 - P)
now we substitute
n = (1.96 / 0.04)² × 0.5 ( 1 - 0.5)
n = 2401 × 0.5 × 0.5
n = 600.25 ≈ 601
Therefore the minimum sample size of the adults in United State who have sleep deprivation is 601
That would be net income (amount made after taxes have been deducted) and hourly wage (amount made per hr at work)
Answer:
c = 4(d) + .43(m)
Step-by-step explanation:
We can test this by plugging in numbers for each of the variables. Let's say Jamal drove 5 miles over 2 days.
c = 4(2) + .43(5)
c = 8 + 2.15
c = $10.15
Have a nice day!
4 divided by 2 is 2. So, 1/2 of one bar goes to each player.
