HELP ME ! beautiful people that are good at math

Jean is trying to read her grocery receipt , but it is blurry . the sales tax rate was 7.75% . she pays tax only on the Items la

Margaret [11]

$12.79+$3.39=$16.18
$16.18+7.75% tax is $1.253

5 0

3 years ago

Eugene had 24$ to spend on three pencils. After buying them he had 18$. How much did each pencil coast?

Helga [31]

Each pencil costed $2.

7 0

3 years ago

Find the maclaurin series for f(x) using the definition of a maclaurin series. [assume that f has a power series expansion. do n

Nady [450]

The equation of $f(x) = e^{-6x}$ by maclaurin series is $f(x)=\sum_{i=0}^{\infty} \frac{(-6.x)^{i} }{i!}$ .

The maclaurin series for f(x) is defined by the following formula:

$f(x) = \sum_{i=0}^{\infty} \frac{f^{(i)} (0)}{i!} .x^{i}$ --------------(1)

Where $f^{i}$ is the i - th derivative of the function

If f(x) = $e^{-6x}$ , then the formula of the i - th derivative of the function is:

$f^{i} =(-6)^{i} .e^{-6x}$ ----------------------(2)

Then,

$f^{i}(0) = (-6)^{i}$

Lastly, the equation of the trascendental function by Maclaurin series is: $f(x)=\sum_{i=0}^{\infty} \frac{(-6)^{i}.x^{i} }{i!} \\f(x)=\sum_{i=0}^{\infty} \frac{(-6.x)^{i} }{i!}$ ---------------(3)

Hence,

The equation of $f(x) = e^{-6x}$ by maclaurin series is $f(x)=\sum_{i=0}^{\infty} \frac{(-6.x)^{i} }{i!}$ .

Find out more information about maclaurin series here

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4 0

1 year ago

One household is to be selected at random from a town. The probability that the household has a cat is 0.20.2 . The proba

dimulka [17.4K]

Answer:

There is a 50% probability that the household has a dog, given that the household has a cat.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a household has a cat.

B is the probability that a household has a dog.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a household has a cat but not a dog and $A \cap B$ is the probability that a household has both a cat and a dog.

By the same logic, we have that:

$B = b + (A \cap B)$

The probability that the household has a cat or a dog is 0.5

$a + b + (A \cap B) = 0.5$

The probability that the household has a dog is 0.4

$B = 0.4$

$B = b + (A \cap B)$

$b = 0.4 - (A \cap B)$

The probability that the household has a cat is 0.2.

$A = 0.2$

$A = a + (A \cap B)$

$a = 0.2 - (A \cap B)$

So

$a + b + (A \cap B) = 0.5$

$0.2 - (A \cap B) + 0.4 - (A \cap B) + (A \cap B) = 0.5$

$A \cap B = 0.1$

What is the probability that the household has a dog, given that the household has a cat?

20% of the households have a cat, and 10% have both a cat and a dog. So

$P = \frac{A \cap B}{A} = {0.1}{0.2} = 0.5$

There is a 50% probability that the household has a dog, given that the household has a cat.

4 0

2 years ago

8000 + 8800 + 8000 + 8 million + 80 trillion + another a katrillion equals

Yuri [45]

Answer:

8,000,802,4800

Step-by-step explanation:

Katrillion isn't a real value but everything else is.

5 0

3 years ago