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photoshop1234 [79]
3 years ago
12

How to complete the proof

Mathematics
1 answer:
meriva3 years ago
5 0
You done that's how you do it<span />
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2/5,1.4,1/3,0.5 in least to greatest
Jobisdone [24]
 1/3 2/5 0.5 1/4 here is ur answer



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3 years ago
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Solve for N, <br><br> −2p + 6n = 5
topjm [15]

Answer:

n=\frac{1}{3}p+\frac{5}{6}

Step-by-step explanation:

In this question, you are solving for n.

Solve:

−2p + 6n = 5

We have to get "n" by itself, so add 2p to both sides.

6n = 2p + 5

Since the variable "n" has a number next to it, we have to get rid of that number in order to get our answer.

To do so, we would divide both sides by 6.

n=\frac{2}{6}p+\frac{5}{6}

Simplify the equation further.

n=\frac{1}{3}p+\frac{5}{6}

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2 years ago
Numbers that are easy to compute using mentally are called?
SVEN [57.7K]
The answer of that is called a compatible number. I hope this helps! :)
8 0
3 years ago
Can you please answer the question?
Roman55 [17]

The <em>trigonometric</em> expression \frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1} is equivalent to the <em>trigonometric</em> expression \sec \alpha \cdot \csc \alpha + 1.

<h3>How to prove a trigonometric equivalence</h3>

In this problem we must prove that <em>one</em> side of the equality is equal to the expression of the <em>other</em> side, requiring the use of <em>algebraic</em> and <em>trigonometric</em> properties. Now we proceed to present the corresponding procedure:

\frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1}

\frac{\tan^{2}\alpha}{\tan \alpha - 1} + \frac{\frac{1}{\tan^{2}\alpha} }{\frac{1}{\tan \alpha} - 1 }

\frac{\tan^{2}\alpha}{\tan \alpha - 1} - \frac{\frac{1 }{\tan \alpha} }{\tan \alpha - 1}

\frac{\frac{\tan^{3}\alpha - 1}{\tan \alpha} }{\tan \alpha - 1}

\frac{\tan^{3}\alpha - 1}{\tan \alpha \cdot (\tan \alpha - 1)}

\frac{(\tan \alpha - 1)\cdot (\tan^{2} \alpha + \tan \alpha + 1)}{\tan \alpha\cdot (\tan \alpha - 1)}

\frac{\tan^{2}\alpha + \tan \alpha + 1}{\tan \alpha}

\tan \alpha + 1 + \cot \alpha

\frac{\sin \alpha}{\cos \alpha} + \frac{\cos \alpha}{\sin \alpha} + 1

\frac{\sin^{2}\alpha + \cos^{2}\alpha}{\cos \alpha \cdot \sin \alpha} + 1

\frac{1}{\cos \alpha \cdot \sin \alpha} + 1

\sec \alpha \cdot \csc \alpha + 1

The <em>trigonometric</em> expression \frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1} is equivalent to the <em>trigonometric</em> expression \sec \alpha \cdot \csc \alpha + 1.

To learn more on trigonometric expressions: brainly.com/question/10083069

#SPJ1

6 0
2 years ago
What is Robin’s distance per stride?
photoshop1234 [79]

Answer:

2 2/3

Step-by-step explanation:

7 0
2 years ago
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