ANSWER:
r = 
Explaination:
Convert the given curve into the the polar form.
x = rcosθ
y = rsinθ
in f(x,y) = (x²-y²) - √(x²+y²) = 0
put the values of x & y in given curve equation.
We get at,
g(r,θ) = (r²cos²θ - r²sin²θ) - √(r²cos²θ + r²sin²θ) = 0
g(r,θ) = r²(cos²θ - sin²θ) - √r² = 0
We know that,
cos²θ - sin²θ = cos2θ
g(r,θ) = r²(cos2θ) - r = 0
Solve for r
Finally we get:
r =
Answer:
See below
Step-by-step explanation:
22. 30 = 2 * 3 * 5
23. 126 = 2 * 3 * 3 * 7
24. 4900 = 2 * 2 * 5 * 5 * 7 * 7
25. 39204 = 2 * 2 * 3 * 3 * 3 * 3 * 11 * 11
26. There's no square number
27. The highest common factor are
30 is 5
126 is 7
4900 is 7
39204 is 11
28. The lowest common factor are
30 is 2
126 is 2
4900 is 2
39204 is 2
What about you? What did you get?
The roots of the polynomial <span><span>x^3 </span>− 2<span>x^2 </span>− 4x + 2</span> are:
<span><span>x1 </span>= 0.42801</span>
<span><span>x2 </span>= −1.51414</span>
<span><span>x3 </span>= 3.08613</span>
x1 and x2 are in the desired interval [-2, 2]
f'(x) = 3x^2 - 4x - 4
so we have:
3x^2 - 4x - 4 = 0
<span>x = ( 4 +- </span><span>√(16 + 48) </span>)/6
x_1 = -4/6 = -0.66
x_ 2 = 2
According to Rolle's theorem, we have one point in between:
x1 = 0.42801 and x2 = −1.51414
where f'(x) = 0, and that is <span>x_1 = -0.66</span>
so we see that Rolle's theorem holds in our function.
Slope = (-14-1)/(7-1) = -15/6
y = mx + c
y = -15/6 x + c
at (1,1)
1 =-15/6(1) + c
c = 1 + 15/6 = 21/6
y = -15/6 x + 21/6 or
6y = -15x + 21
