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1 year ago

1) The following scatterplot shows the percentage of the vote a candidate received in the 2016 senatorial elections

1 answer:

3 0

Option C is correct. The test statistic is not between the critical values, so we reject the null hypothesis. There is sufficient evidence to support a claim of correlation between percentage of vote and income level.

<h3>How to find the correlation</h3>

The scatter plot is the plot that is used to show the correlation that is known to exist between the given data sets that is of interests. It helps by showing the existing relationship between the x values and the y values in the question.

When we look at the graph properly, if we are to rule a line we would find out that most of the data points in the equation fall under the line in the data set. This shows that there is high correlation between these two variables.

Read more on scatter plot here: brainly.com/question/6592115

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Help me pleaseeee thank you sm

Leno4ka [110]

Answer:

The answer is A) 379.9

Step-by-step explanation:

3.14(11^2)

3.14*11^2

3.14*(11*11)

379.94 if rounded to the nearest tenth it would be 379.9

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2 years ago

WHAT WOULD THIS BEEEE!!

Alekssandra [29.7K]

The answer is d :) have a good day

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2 years ago

A circular garden with a radius of 8 feet is surrounded by a circular path with a width of 3 feet. What is the approximate area

ziro4ka [17]

Answer:

9.42?

Step-by-step explanation:

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3 years ago

Read 2 more answers

What is equal to the expression (4^-5)^3

Leona [35]

The answer is 1/1073741824 or about 9.313 * 10^-10

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3 years ago

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A recent study found that the average length of caterpillars was 2.8 centimeters with a

pogonyaev

Using the normal distribution, it is found that there is a 0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, the mean and the standard deviation are given, respectively, by:

$\mu = 2.8, \sigma = 0.7$ .

The probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters is <u>one subtracted by the p-value of Z when X = 4</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{4 - 2.8}{0.7}$

Z = 1.71

Z = 1.71 has a p-value of 0.9564.

1 - 0.9564 = 0.0436.

0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

More can be learned about the normal distribution at brainly.com/question/24663213

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4 0

2 years ago