Answer:
B.)The volume of the triangular prism is not equal to the volume of the cylinder.
Step-by-step explanation:
Let A be the cross-sectional area of both congruent right triangular prism and right cylinder.
Since the prism has height 2 units, its volume V₁ = 2A.
Since the cylinder has height 6 units, its volume is V₂ = 6A
Dividing V₁/V₂ = 2A/6A =1/3
V₁ = V₂/3.
The volume of the prism is one-third the volume of the cylinder.
So, since the volume of the prism is neither double nor half of the volume of the cylinder nor is it equal to the volume of the cylinder, B is the correct answer.
So, the volume of the triangular prism is not equal to the volume of the cylinder.
Answer:
B. 40
Step-by-step explanation:
It looks like a 90-degree angle so...
90 - 30 = 60
60 - 20 = 40
40 would be your final answer.
Answer:
3x^2 -7x +2
Step-by-step explanation:
(15x^2 -35x +10)÷5
15/5 x^2 -35/5 x +10/5
3x^2 -7x +2
We have that
<span>tan(theta)sin(theta)+cos(theta)=sec(theta)
</span><span>[sin(theta)/cos(theta)] sin(theta)+cos(theta)=sec(theta)
</span>[sin²<span>(theta)/cos(theta)]+cos(theta)=sec(theta)
</span><span>the next step in this proof
is </span>write cos(theta)=cos²<span>(theta)/cos(theta) to find a common denominator
so
</span>[sin²(theta)/cos(theta)]+[cos²(theta)/cos(theta)]=sec(theta)<span>
</span>{[sin²(theta)+cos²(theta)]/cos(theta)}=sec(theta)<span>
remember that
</span>sin²(theta)+cos²(theta)=1
{[sin²(theta)+cos²(theta)]/cos(theta)}------------> 1/cos(theta)
and
1/cos(theta)=sec(theta)-------------> is ok
the answer is the option <span>B.)
He should write cos(theta)=cos^2(theta)/cos(theta) to find a common denominator.</span>