Answer:
$42
Step-by-step explanation:
40% of $63 is $25.2
$63 - $25.2 = $37.8
How much your paying without tax 37.8
7% of $63 is $4.41.
$37.8 + $4.41 = $42.21
Rounded 42.21 = 42
Im not 100% sure about the rounding but I hope this helps!
GCF is 5m^2 n^2
m^2 has exponent 2 and n^2 has exponent 2
(1) m^5n^5
here there is no 5 so it does not have GCF
(2) 5m^4n^3
m^4 has exponent 4 greater than exponent 2
n^3 has exponent 4 greater than exponent 2
5m^4n^3 have GCF
(3) 10m^4n
10 is 5*2 . it has GCF 5
m^4 has exponent 4 greater than exponent 2
n has exponent 1 less than exponent 2
10m^4n does not have GCF
(4) 15m^2n^2
15 is 3*5 which has GCF 5
m^2 has exponent 2 which is equal to exponent 2
n^2 has exponent 2 which is equal to exponent 2
15m^2n^2 have GCF
(5) 24m^3n^4
24 is 2*2*2*3 does not have GCF
m^3 has exponent 3 greater than exponent 2
n^4 has exponent 4 greater than exponent 4
24m^3n^4 does not have GCF
Answer: The three consecutive odd integers are: -15, -13, and -11 .
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Explanation:
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x + (x + 2) + (x + 4) = -39 ;
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in which "x" is one of the integers,
"(x + 2)" is the next consecutive odd integer;
"(x + 4)" is the third consecutive odd integer.
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By solving for "x", we can solve for each of three (3) consecutive odd integers.
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x + (x + 2) + (x + 4) = -39 ;
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1x + 1x + 2 + 1x+ 4 = -39 ;
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3x + 6 = -39 ;
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Subtract "6" from EACH side of the equation:
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3x + 6 − 6 = -39 <span>− 6 ;
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to get: 3x = -45 ;
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Divide EACH side of the equation by "3" ;
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3x / 3 = -45 / 3 ;
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to get: x = -15 ;
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x + 2 = -15 + 2 = -13 ;
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x + 4 = -15 + 4 = -11 .
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Are: -15, -13, and -11 ; Consecutive odd integers? YES!
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Does: -15 + (-13) + (-11) =? = -39 ??
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-15 </span>− 13 <span>− 11 = ? 39 ?? YES!
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Answer: The three consecutive odd integers are: -15, -13, and -11.
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For this case we have that Lauren's initial amount of money was $ 50, if he spends $10 and $12 on admission and strawberry pie respectively we have:
$50 - ($10 + $12) = $50- $22 = $28
That is, she has $ 28 left
n: Let the variable that represents the amount of games Lauren can play.
Then, it must be fulfilled that:
Thus, Lauren can play 37 times the game (at most)
ANswer:
Thus, Lauren can play 37 times the game (at most)
