Answer:
Divide the number of contestants by 4 and when there is 120 contestants there is 30 winners
Step-by-step explanation:
Looking back at past sequences we can see that when we had 8 contestants we had 2 winners 8/4=2 and we also saw 16/4=4 so that was the formula now we just had to do it on 120 contestants and now we get 30 winners....Hope this helps! :)
Answer:
a) Cancellations are independent and similar to arrivals.
b) 22.31% probability that no cancellations will occur on a particular Wednesday
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given time interval.
Mean rate of 1.5 per day on a typical Wednesday.
This means that 
(a) Justify the use of the Poisson model.
Each wednesday is independent of each other, and each wednesday has the same mean number of cancellations.
So the answer is:
Cancellations are independent and similar to arrivals.
(b) What is the probability that no cancellations will occur on a particular Wednesday
This is P(X = 0).


22.31% probability that no cancellations will occur on a particular Wednesday
Answer:
120 for oxen, 80 for cows, 60 for calves
o = 2x
Step-by-step explanation:
3o + 4x + 6c = 260
x = 2c
o = 2x
6x + 4x + 3x = 260
13x = 260
260 / 13 = 20
3o = 6x = 120
4x = 80
6c = 3x = 60
o = 2x
Answer:
1st sphere has r1 = 6
=> Surface area S1 = 4 x pi x r1^2 = 4 x pi x 6^2 = 144pi
=> Volume V1 = (4/3) x pi x r1^3 = (4/3) x pi x 6^3 =288pi
2nd sphere has r1 = 15
=> Surface area S1 = 4 x pi x r1^2 = 4 x pi x 15^2 = 900pi
=> Volume V1 = (4/3) x pi x r1^3 = (4/3) x pi x 15^3 =4500pi
=> S1/S2 = 144pi/900pi = 0.16
=> V1/V2 = 288pi/4500pi = 0.064
Hope this helps!
:)