We have the given I = 10^-1 and I₀ = 10^-12.
Simply plugging in the values to the equation, we have:
L = 10log(10^-1/10^-12)
L = 110 Db
The answer is D.
(I used a scientific calculator in solving for L).
Multiplying complex numbers is a lot like multiplying binomial terms. The only relation one has to remember when dealing with complex numbers is that i² = -1.
Now let us try to multiply binomials. This is done by adding the products of the first term of the first binomial distributed to the second binomial, and the second term of the first binomial distributed to the second binomial. This is done below:
(<span>3 – 5i)(–2 + 4i) = -6 + 12i + 10i -20i²
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Simplifying and applying i²<span> = -1:</span>
-6 + 22i - 20(-1)
-6 + 22i + 20
14 + 22i
Among the choices, the correct answer is B.
Answer:
-2
Step-by-step explanation:
x + 3 = -(x + 1)
open the bracket
x + 3 = -x -1
x+x= -1-3
2x= -4
X = -4/2= -2
Answer 70 = 7070
Step-by-step explanation: denotes how many times to multiply the base (70)
Answer:
-16 - 6 would be -22
Step-by-step explanation: The reason for this is is simple subtraction except in this case you wanna think of addition. -16 - 6 can also be thought of 16+6. In that case you get 22 and then you just add the negative sign.
