Answer:
XF·XG = 17
Step-by-step explanation:
Drawing a cyclic quadrilateral from side lengths is interesting enough. I have no idea how to compute the desired value, but my geometry program says it is 17.
In the attached, XF is line segment m, approximately 7.63 in length. XG is line segment n, approximately 2.23 in length. The product is the number "o", shown at the end of the red arrow.
2. x + y = 82
x - y = 24
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2x = 106
x = 53
x + y = 82
53 + y = 82
y = 82 - 53
y = 29
solution is : (53,29)
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3. y = 2x
y = 4x + 6
2x = 4x + 6
2x - 4x = 6
-2x = 6
x = -3
y = 2x
y = 2(-3)
y = -6
solution is (-3,-6)
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4. 5x + 8y = -29
7x - 2y = -67...multiply by 4
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5x + 8y = -29
28x - 8y = - 268 ..result of multiplying by 4
-----------------add
33x = - 297
x = - 9
5x + 8y = -29
5(-9) + 8y = -29
-45 + 8y = -29
8y = -29 + 45
8y = 16
y = 2
solution is : (-9,2)
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5. y = -4x + 6
y = -5x - 4
-4x + 6 = -5x - 4
-4x + 5x = -4 - 6
x = -10
y = -4x + 6
y = -4(-10) + 6
y = 40 + 6
y = 46
solution is (-10,46)
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6. H(m) = 2m + 12
H(m) = 3m + 10
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7. -8x + 4y > -52
4y > 8x - 52
y > 2x - 13 <==
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8. 3x - y = 28
3x + y = 14
---------------add
6x = 42
x = 7
3x - y = 28
3(7) - y = 28
21 - y = 28
-y = 28 - 21
-y = 7
y = -7
solution is (7,-7)
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10. 5x - 5y > 70
-5y > -5x + 70
y < x - 14 <==
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11. sorry...dont know
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12. y = 4x + 4
y = -3x - 3
4x + 4 = -3x - 3
4x + 3x = -3 - 4
7x = -7
x = -1
y = 4x + 4
y = 4(-1) + 4
y = 0
solution is (-1,0)
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13. -12x - 2y > - 42
-2y > 12x - 42
y < -6x + 21 <==
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14. -5x + 2y = 9
3x + 5y = 7
solution is (-1,2)
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15. 3x + 6y = -2
15x + 30y = -10....divide by 5 to reduce = 3x + 6y = -2
is the same line....infinite solutions
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1. (the graph).....y < = 3x - 4....3rd one
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9. (2nd graph)....y < = -3x + 4....last one
ill help but where is the clock?
