A computer simulation tossed a 10-faced die 5 times

Mathematics

2 answers:

Leviafan [203]4 years ago

8 0

Answer: 100,000

Step-by-step explanation:

The number of possible outcomes for 10 faced dice = 10

If a computer simulation tossed a 10-faced die 5 times, then the possible outcomes exist = $10^5=10\times10\times10\times10\times10$

⇒ The possible outcomes exist =100,000

Hence, If a computer simulation tossed a 10-faced die 5 times, then there are 100,000 possible outcomes exist.

Ganezh [65]4 years ago

3 0

In each toss of the 10 - faced die, there are 10 possible outcomes. To determine the number of possible outcomes that exist after 5 tosses, we multiply 10 by itself 5 times. The operation gives an answer of 100,000. Thus, the answer is the second choice.

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Alexxandr [17]

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$\underline{\text{ GCF of } 44c^5, 22c^3 , 11c^4 :}$