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Rainbow [258]
3 years ago
11

When looking at a graph of a parabola we can find the real solutions by seeing where the graph crosses the:

Mathematics
2 answers:
Lynna [10]3 years ago
5 0

Answer:

The x-axis

Step-by-step explanation:

When the y-value is 0, x value can be anything from -∞ to ∞. So, any solution would lie on the x-axis only when y = 0.

Drupady [299]3 years ago
5 0

Answer:

A. x-axis

Step-by-step explanation:

The solutions of an equation are also thw zeroes of the equation, i.e, the x values where the function is 0

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navik [9.2K]

Hello.

-7h + 2(-4h + 5) > -4h + 1 + 10 ; solve for h

Our first step is to get rid of all the parenthesis. We can do this by simplifying everything out.

-7h - 8h + 10 > -4h + 11

Add like terms.

-15h + 10 > -4h + 11

Now, we must isolate our variables. We do this by moving all variables to one side and moving our other numbers to the other.

Subtract 10 from both sides. Then, add 4h to both sides.

-15h + 4h > 11 - 10

Simplify.

-h > 1

Divide both sides by -1.

However, keep in mind that when dividing with a negative, you must change the sign. Therefore, > turns into <

-h ÷ -1 < 1 ÷ -1

h < -1

6 0
3 years ago
Simplify please quick:<br> 3x4=12-6
den301095 [7]

Answer:

Step-by-step explanation:

3 * 4 = 12 - 6

12 = 6

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3 0
2 years ago
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Which equation represents a hyperbola with a center at (0,0), a vertex at (0,60), and a focus at (0,-65)
Leona [35]
Given that the hyperbola has a center at (0,0), and its vertices and foci are on y-axis. This, the equation of the hyperbola is of the form
x²/a²-y²/b²=-1 (a>0, b>0)
In the equation, vertices are (0, +/-b) .
Thus, 
b=60
Foci (0,+/-√(a²+b²))
thus
√(a²+60²)=65
hence solving for a²
a²=65²-60²
a²=625
a²=25²
hence the equation is:
x²/25²-y²/60²=-1
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3 years ago
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GrogVix [38]

Answer: 10:7

Step-by-step explanation:

40:28=10*7

6 0
3 years ago
What type of shape will the reflected figure be?
julsineya [31]
How does your figure look like?
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