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ahrayia [7]
3 years ago
10

What is the area of the parallelogram?

Mathematics
1 answer:
ch4aika [34]3 years ago
3 0
S = 6*6 = 36 square sentimeters
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Need help plz this is math. Don’t answer if you don’t know. I will give brainliest to the right answer.
Vesna [10]

Answer:

i know that x is an acute angle

Step-by-step explanation:

7 0
2 years ago
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Compare the two fractions using <, >, or =. 6/12 ___ 1/2
Mice21 [21]

Answer:

6/12=1/2

Step-by-step explanation:

6/12_1/12

Reduce 6/12 into lowest form

6/12=1/2

We get,

1/2_1/2

Both are equal,therefore

6/12=1/2

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3 years ago
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What type of function is represented?
tino4ka555 [31]

Answer:

b

Step-by-step explanation:

ITS B NOT C ITS B ITS B ITS B.

3 0
3 years ago
Consider a triangle ABC like the one below. Suppose that a =53, b=18, and A=130º. (The figure is not drawn to scale.) Solve the
ddd [48]

Answer:

B = 15.1°, C = 34.9°, c = 39.6

Step-by-step explanation:

law of sines

53/sin 130 = 18/sin B

sin B = .26;   B = 15.1°

C = 180 - 15.1 - 130 = 34.9°

c/sin 34.9 = 53/sin 130

c = 39.6

8 0
3 years ago
The current population of a town is 10,000 and its growth in years can be represented by P(t) = 10,000(0.2)^t, where t is the ti
DiKsa [7]

Answer:

1) 20%

2) Choice a.

Step-by-step explanation:

P(t)=10000(0.2)^t

1) P(0) is the population initially.

P(1) is the population after a year.

\frac{P(1)}{P(0)} represents the population increase factor.

So let's evaluate that fraction:

\frac{P(1)}{P(0)}

\frac{10000(0.2)^1}{10000(0.2)^0}

\frac{0.2^1}{0.2^0}=\frac{0.2}{1}=0.2

0.2=20%

2) Let's figure out the population growth in terms of months instead of years.

P(t)=10000(0.2)^{t}

We want t to represent months.

A full year is 12 months, in a full year we have that P(1)=10000(0.2)^1=10000(0.2)=2000

So we want a new P such that P(12)=2000 since 12 months equals a year.

Let's look at the functions given to see which gives us this:

a) P(12)=10000(0.87449)^{12}=2000 \text{approximately}

b) P(12)=10000(0.87449)^{12(12)}=0 \text{ approximately}

c) P(12)=10000(0.87449)^{\frac{1}{12}}=9889 \text{approximately}

d) P(12)=10000(0.87449)^{12+12}=400 \text{approximately}

So a is the function we want.

Also another way to look at this:

P(t)=10000(.2)^t where t is in years.

P(t)=10000(.2^\frac{1}{12})^t where t is in months.

And .2^\frac{1}{12}=0.874485 \text{approximately}

8 0
3 years ago
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