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zalisa [80]
2 years ago
12

Can someone help will mark brainlist

Mathematics
1 answer:
Evgen [1.6K]2 years ago
6 0

Answer:

There will be about 18 grams remaining.

Step-by-step explanation:

If you have 500 grams to start and it decreases by 20% each day for 15 days, you can use the following equation:

Remaining amount = 500(1 - 0.20)^{15}

Plug this into a calculator and you should get 17.59218604, which, when rounded to the nearest gram, equals 18 grams remaining.

Hope this helps!

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Let A = {1, 2, 3, 4, 5} and B = {2, 4}. What is A ∩ B?
Harlamova29_29 [7]

A\cap B=\{x:x\in A \wedge x\in B\}

A\cap B=\{2,4\}

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Is someone good at geometry i really need help the question doesnt make sense
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answer
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Step-by-step explanation:

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Suppose that a spherical droplet of liquid evaporates at a rate that is proportional to its surface area: where V = volume (mm3
Alex

Answer:

V = 20.2969 mm^3 @ t = 10

r = 1.692 mm @ t = 10

Step-by-step explanation:

The solution to the first order ordinary differential equation:

\frac{dV}{dt} = -kA

Using Euler's method

\frac{dVi}{dt} = -k *4pi*r^2_{i} = -k *4pi*(\frac {3 V_{i} }{4pi})^(2/3)\\ V_{i+1} = V'_{i} *h + V_{i}    \\

Where initial droplet volume is:

V(0) = \frac{4pi}{3} * r(0)^3 =  \frac{4pi}{3} * 2.5^3 = 65.45 mm^3

Hence, the iterative solution will be as next:

  • i = 1, ti = 0, Vi = 65.45

V'_{i}  = -k *4pi*(\frac{3*65.45}{4pi})^(2/3)  = -6.283\\V_{i+1} = 65.45-6.283*0.25 = 63.88

  • i = 2, ti = 0.5, Vi = 63.88

V'_{i}  = -k *4pi*(\frac{3*63.88}{4pi})^(2/3)  = -6.182\\V_{i+1} = 63.88-6.182*0.25 = 62.33

  • i = 3, ti = 1, Vi = 62.33

V'_{i}  = -k *4pi*(\frac{3*62.33}{4pi})^(2/3)  = -6.082\\V_{i+1} = 62.33-6.082*0.25 = 60.813

We compute the next iterations in MATLAB (see attachment)

Volume @ t = 10 is = 20.2969

The droplet radius at t=10 mins

r(10) = (\frac{3*20.2969}{4pi})^(2/3) = 1.692 mm\\

The average change of droplet radius with time is:

Δr/Δt = \frac{r(10) - r(0)}{10-0} = \frac{1.692 - 2.5}{10} = -0.0808 mm/min

The value of the evaporation rate is close the value of k = 0.08 mm/min

Hence, the results are accurate and consistent!

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Answer:

The answer is noncollinear

Step-by-step explanation:

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