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3 years ago

Which equations represent the line that is parallel to 3x − 4y = 7 and passes through the point (−4, −2)?

Mathematics

1 answer:

Alekssandra [29.7K]3 years ago

6 0

It’s going to be -5 if you believe it or not or , -2

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= 800 + 320 + 40 + 16 Hope this helped.

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Which table represents a linear function?

vesna_86 [32]

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How long did lizzie practice on thursday and friday altogether<br> free brainliest

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1 year ago

At a high school, students can choose between three art electives, four history electives, and five computer electives. Each stu

aleksandrvk [35]

Answer:

(3C1 × 4C1)/12C2

Step-by-step explanation:

Total electives = 3 + 4 + 5 = 12

Art: 3C1

History: 4C1

1 Art & 1 History = 3C1 × 4C1

Probability = (3C1 × 4C1)/12C2

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3 years ago

Read 2 more answers

The median of a probability distribution can be defined as the number m such that Upper P (Upper X less than or equals m )equals

Alexxandr [17]

Answer:

tex]M=\beta ln(2)[/tex]

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate).

Solution to the problem

For this case we can use the following Theorem:

"If X is a continuos random variable of the exponential distribution with parameter $\beta$ for some $\beta \in R >0$ "

Then the median of X is $\beta ln (2)$

Proof

Let M the median for the random variable X.

From the definition for the exponential distribution we know the denisty function of X is given by:

$f_X (x) = \frac{1}{\beta} e^{-\frac{x}{\beta}}$

Since we need the median we can put this equation:

$P(X$

If we evaluate the integral we got this:

$\frac{1}{\beta} \int_0^M e^{- \frac{x}{\beta}}dx =\frac{1}{\beta} [-\beta e^{-\frac{x}{\beta}}] \Big|_0^M$

And that's equal to:

$1/2 = 1 -e^{- \frac{M}{\beta}}$

And if we solve for M we got:

$1-e^{- \frac{M}{\beta}} = \frac{1}{2}$

$e^{- \frac{M}{\beta}}=\frac{1}{2}$

If we apply natural log on both sides we got:

$-\frac{M}{\beta}=ln(1/2)$

And then $M=\beta ln(2)$

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3 years ago