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3 years ago

5

Galina had two boxes with pieces of paper in each. In the first box, each piece of paper had one possible outcome from flipping

a coin 4 times (e.g. HHTH). There was one piece of paper for every possible outcome.
How many pieces of paper were in the first box?

1 answer:

Natali5045456 [20]3 years ago

3 0

Answer:

B

Step-by-step explanation:

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HELP! THIS IS DUE AT 10:40!!!!!!

katrin2010 [14]

Answer:

Yes

Step-by-step explanation:

Both quadrilaterals have two triangles. The triangles that coordinate with the triangles in the other quadrilateral are proven congruent by AAS and AA. That makes the quadrilaterals congruent.

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3 years ago

HURRY!!! I WILL GIVE BRAINLIEST FOR CORRECT ANSWER

Sergeeva-Olga [200]

Answer:

A function is a relation in which each element of the domain, or x-value, is mapped to one element of the range, or y-value.

The question we are asked is if cost is a function of the activity type. This means that cost would be the range and activity type would be the domain.

If this is a function, then each activity type would have only one cost. However, on different days of the week each activity type has different prices; this means there is more than one cost for each activity type, and it is not a function.

8 0

3 years ago

What is the rate of change?

eduard

Answer:

12

Step-by-step explanation:

12 +30= 42

42+12=54

4 0

3 years ago

2z-18-4z=-8 what is the value of z

zmey [24]

The z is 5

−2⋅<em>z</em>=−8+18

-

2

⋅

z

=

-

8

+

18

Simplify :

−2⋅<em>z</em>=10

-

2

⋅

z

=

10

Dividing by the variable coefficient :

<em>z</em>=−

10

2

z

=

-

10

2

Simplify :

<em>z</em>=−5

z

=

-

5

The solution of equation

2⋅<em>z</em>−18−4⋅<em>z</em>=−8

2

⋅

z

-

18

-

4

⋅

z

=

-

8

is

[−5]

7 0

3 years ago

The junior and senior students at Mathville High School are going to present an exciting musical entitled, "Math, What is it Goo

xeze [42]

Some parts are missing in the queston. Find attached the picture with the complete question

Answer:

$\large\boxed{\large\boxed{161}}$

Explanation:

Let's put the information in a table step-by step.

(number of remaining students)

Juniors Seniors

Condition

Initially J S

15 seniors left S - 15

Twice juniors as seniors 2(S - 15)

3/4 of the juniors left 1/4×2(S - 15)
1/3 of seniors left 2/3×(S - 15)

At the end, there were 8 more seniors than juniors:

2/3×(S - 15) - 1/4×2(S - 15) = 8

Now you have obtained one equation, which you can solve to find S, the number of senior students, and then the number of junior students.

Solve the equation:

$2/3\times (S - 15) - 1/4\times 2(S - 15) = 8$

Mutilply all by 12:

$8(S - 15)-6(S - 15)=96$

Distribution property:

$8S-120-6S-90=96$

Addtion property of equalities:

$8S-6S=96+120+90$

Add like terms:

$2S=306$

Division property of equalities:

$S=306/2=153$

That is the number of senior students that came out to the information meeting, but the number of students remaining to perform in the school musical is (from the table above):

$2/3\times (S-15)+1/4\times 2(S-15)$

Just substitute S with 153 fo find the number of students that remained to perfom in the musical:

$2/3\times (153-15)+1/4\times 2(153-15)\\ \\ 2/3(138)+1/2(138)$

$161$

5 0

3 years ago