What number line represents the solution to the inequality below -6< -2x

The given values are discrete. Use the continuity correction and describe the region of the normal distribution that corresponds

Lerok [7]

Answer:

$P_B(X\leq35)=P_N(X$

Step-by-step explanation:

If we approximate the binomial distribution with a normal distribution, we have to apply a correction factor for the fact that we are now dealing with a continuous variable instead of a discrete one, as it was with the binomial distribution.

The probability of no more than 35 defective CDs: P(X<35)

In this case, as X=35 is not included in the interval, we start the interval from X=35-0.5=34.5.

$P_B(X\leq35)=P_N(X$

being Pb the probability under the binomial distribution and Pn the probability under the normal distribution.

The area for the normal distribution is the one below X=34 (or P(X<34)).

4 0

3 years ago

One leg of a right triangle is 4 cm the hypotenuse is 10 cm how long it the other leg

ASHA 777 [7]

I hope this will work.

3 0

3 years ago

Read 2 more answers

An instructor who taught two sections of engineering probability last term, the first with 20 students and thesecond with 30, de

Oliga [24]

Answer:

0.207

Step-by-step explanation:

This is an hypergeometric distribution problem

An hypergeometric distribution has the same sense as the discrete probabilities of binomial distribution, but unlike binomial distribution, hypergeometric distribution does not allow replacement.

Binomial distribution expresses the probability of picking k objects from n with replacement, but hypergeometric distribution expresses picking k objects from n without replacement, with the finite total population, N, containing K objects.

It is expressed mathematically as

h(k: n, K, N) = (ᴷCₖ)(ᴺ⁻ᴷCₙ₋ₖ)/(ᴺCₙ)

where

k = number of students in the 2nd section required to be in the first 15 graded projects (number of successes) = 10

n = total number of first graded projects (number of trials) = 15

K = number of students in the 2nd section of the class = 30

N = total number of students = 50

h(10: 15, 30, 50) = (³⁰C₁₀)(⁵⁰⁻³⁰C₁₅₋₁₀)/(⁵⁰C₁₅)

h(10: 15, 30, 50) = (³⁰C₁₀)(²⁰C₅)/(⁵⁰C₁₅)

= (30,045,015)(15,504)/(2,250,829,575,120)

P(X = 10) = 0.207

Hope this Helps!!!

7 0

3 years ago

I cant seem to understand this. please explain :)) (business math)

Alex787 [66]

Answer:

$1.50 bro

Step-by-step explanation:

4 0

3 years ago

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159.98 divided by 6 ASAPP

ArbitrLikvidat [17]

159.98 divided by 6 is 26.66, hopefully this is correct...

4 0

3 years ago

What number line represents the solution to the inequality below-6< -2x