3/4 on the minute hand of a clock would be 45.
example: 6:45
114 is the answer hope this helps good luck and god bless!
Answer:
(a)
Shortest Side of the trapezoid =6 yds
Longest Side =8 yds
(b)42 Square Yards
Step-by-step explanation:
<u>Part A</u>
In the Trapezoid, Width =6 yd
Since the shortest side of the playground and its width have the same dimension, then:
- Shortest Side of the trapezoid =6 yd
<u>Part B</u>
Area of the Playground
In the trapezoid
a=6 yd, b=8 yd, h=Width=6 yd
Area of a trapezoid
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Answer:
A) answer c ; B) X+3.7=15.3 ; C) 15.3 - 3.7 = 11.6 ---> 11.6+3.7=15.3
Step-by-step explanation:
Solution for A: First you have to look for the line underneath the bar says 15.3 as this will represent the total amount of liters in the bucket altogether. This would be bar c since we also know that we have 3.7 liters added but are missing the amount that was previously inside the bucket.
Solution for B: Let X resemble the unknown amount of water. To solve B, we need to write an equation. We know that there was already an amount of water in the bucket prior to us pouring more in so X is our first addend. We then added 3.7 liters of water to the unknown amount so that is our next addend giving you X+3.7=15.3
Solution for C: Now that we know our equation, we do the inverse operation (subtraction) in order to figure out the missing amount of water. This means we do
15.3 - 3.7 = 11.6
Given :
The Mad Hat Company must ship two different-sized boxes: The small ones cost them 45 cents each and weigh 6 ounces, and the large ones weigh 25 ounces and cost $1.20 each.
The total shipment this morning weighed 20 pounds 7 ounces and cost $18.45.
To Find :
How many packages of each size were shipped.
Solution :
We know, 1 pound = 16 ounces.
So, 20 pound = 20×16 = 320 ounces.
Let, number of large and small box are l and s.
So,
25l + 6s = 327 ...1)
0.45s + 1.20l = 18.45 ...2)
Solving both the equations, we get :
x = 9 and y = 17
Therefore, package smaller and big size are 17 and 9 respectively .
Hence, this is the required solution.
